A runner is training for an upcoming marathon by running around a 80-m-diameter circular track at constant speed. Let a coordina
1 answer:
Answer:
Explanation:
Given
diameter
runner start at (x,y)=(48 m,0 m)
Runner runs around the circle 2.5 times
i.e. he runs two and half rounds
displacement of two rounds is zero so net displacement is of half round
displacement
After 2.5 round he will be towards west direction with respect to origin
so direction of displacement vector is west
You might be interested in
Answer:
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
Explanation:
A vehicle crash problem must be solved with the equation of the moment,
Initial instant Before crash
p₀ = m v₁ + mv₂
After the crash
= m
+ m
p₀ =
If the speed ratio before and after the crash is one
p₀ / = 1
We can assume that initially one of the cars was stopped
m v₁₀ = m
v₁₀ =
For the two speeds to be equal, the masses of the vehicles must be the same.
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
Answer
given,
time = 10 s
ship's speed = 5 Km/h
F = m a
a is the acceleration and m is mass.
In the first case
F₁=m x a₁
where a₁ = difference in velocity / time
F₁ is constant acceleration is also a constant.
Δv₁ = 5 x 0.278
Δv₁ = 1.39 m/s
a₁ = 0.139 m/s²
F₂ =m x a₂
F₃ = F₂ + F₁
Δv₃ = 19 x 0.278
Δv₃ = 5.282 m/s
a₃=Δv₂ / t
a₃ = 0.5282 m²/s
m a₃=m a₁ + m a₂
a₃ = a₂ + a₁
0.5282 = a₂ + 0.139
a₂=0.3892 m²/s
F₂ = m x 0.3892...........(1)
F₁ = m x 0.139...............(2)
F₂/F₁
ratio =
ratio = 2.8