The following reaction, catalyzed by iridium, is endothermic at 700 K: CaO(s) + CH4(g) + 2H2O (g) → CaCO3 (s) + 4H2 (g) For the
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Answer:
Explanation:
1) Molarity of the solution is (0.50/0.75)x1 = 0.66666 Mol/L
2) Molar mass of NaCl is 23+35 = 58g
Molarity = (0.5/58)/0.075 = 0.115 Mol/L
3) Molar mass of = 7x2 + 32 + 16x2 = 78g
Molarity = (734/78)/0.875 = 10.754 Mol/L
5) Molar mass of
= 207.2 + ((12x2) + (1x3) + (16x2))x4
= 207.2 + (24+3+32)x4 = 443.2g
Molarity = (0.0672/443.2)/0.1335 = 0.001135 Mol/L
6) Both are the same.
Solution 1 Molarity = 1.0/1.0 = 1 Mol/L
Solution 2 Molarity = 1.0/1.0 = 1 Mol/L
Molarities of the solutions are the same.
First, find the number of moles for each element. The molar mass for nitrogen is 14 g/mol and that of hydrogen is 1 g/mol.
1.40 g N / 14 g/mol = 0.1 mol N
0.20 g H / 1 g/mol = 0.2 mol H
Find the mole ratio. Divide both numbers with the much lower value. In this case, it is 0.1 mol N.
For N: 0.1 ÷ 0.1 = 1
For H: 0.2÷0.1 = 2
Thus, the empirical formula is .