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3 years ago

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as earth rotates about it’s axis, it takes three hours for the united states to pass beneath a point above earth that is station

ary relative to the sun. What is wrong with the following scheme? to travel from washington, D.C. to san francisco shoving very little fuel, simply ascend in a helicopter high over washington, D.C. and wait three hours until san francisco passes below

1 answer:

pickupchik [31]3 years ago

6 0

interesting question.

how much fuel to hover over one place ?

The Foucault pendulum is a v v v long pendulum which can show the eart's rotation over time if the pend bob motion is tracked and recorded

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A 6.0 MeV alpha particle beam of cross section 5 cm2 is completely stopped in an ionization chamber producing a saturation curre

Licemer1 [7]

Answer:

$v=6.0MeV\\h=6.626\cdot10^{-34}\\dq=33\\$

Solution

$m_\alpha =6.64\cdot 10^{-27}\\\lambda=\frac{h}{p}\\p=\sqrt{2m\cdot V}\\\lambda=\frac{6.628 \cdot10^{-34}}{\sqrt{2(6.64\cdot10^{-27})(6\cdot10^6)}}\\\\\lambda =2.35\cdot10^{-34}\\Fluence Rate =\frac{d(N)}{d(t)\cdot d(S)}=\frac{d(N)\cdot d(q)}{d(q)\cdot d(t)\cdot d(S)}=\frac{d(N)}{d(q)}\frac{V} {\cdot d(S)}\\\\\=\frac{6\cdot 10^6}{33} \cdot\frac{0.08\cdot10^{-9}}{4\cdot\pi\cdot25\cdot10^{-4}}\\\\=0.000463\\E_p=4.63\cdot10^{-4}\\$

$=\frac{6*10^6\cdot 0.08*10^{-9}}{33\cdot4\pi\cdot 25*10^-4} \\\\E_P=4.63*10^{-4}$

Explanation:

First enlist all the variables

then solve using calculator

6 0

4 years ago

Two 10-cm-diameter metal plates 1.0 cm apart are charged to {12.5 nC. They are suddenly connected together by a 0.224-mm- diamet

Alekssandra [29.7K]

Answer:

(a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Explanation:

Given that,

Diameter of metal plates = 10 cm

Distance between the plates = 1.0 cm

Charged = 12.5 nC

Diameter of copper wire = 0.224 mm

We need to calculate the cross section area of the plates

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times(5\times10^{-2})^2$

$A=7.85\times10^{-3}\ m^2$

We need to calculate the capacitor

Using formula of capacitor

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.85\times10^{-3}}{1.0\times10^{-2}}$

$C=6.94\times10^{-12}\ F$

We need to calculate the resistance of the wire

Using formula of resistivity

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.7\times10^{-8}\times1.0\times10^{-2}}{\pi\times(0.1125\times10^{-3})^2}$

$R=4.27\times10^{-3}\ \Omega$

We need to calculate the voltage

Using formula of charge

$q=CV$

$V=\dfrac{q}{C}$

Put the value into the formula

$V=\dfrac{12.5\times10^{-9}}{6.94\times10^{-12}}$

$V=1.801\times10^{3}\ V$

(a). We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}$

$I=\dfrac{1.801\times10^{3}}{4.27\times10^{-3}}$

$I=421779.85\ A$

$I=4.217\times10^{5}\ A$

(b). We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times12.5\times10^{-9}}{(1.0\times10^{-2})^2}$

$E=11.2\times10^{5}\ N/C$

The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c). In this case, the voltage between the capacitor plates decreases as the charge decreases with time.

The current is directly proportional to the voltage between the plates .

Hence, The current also decrease with time.

(d). We need to calculate the total amount of energy dissipated in the wire

Using formula of energy

$E=\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times6.94\times10^{-12}\times(1.801\times10^{3})^2$

$E=1.126\times10^{-5}\ J$

The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Hence, (a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

8 0

3 years ago

Minnie sota hits the end of a bar 1. 2 m long with a hammer. Sketch the standing wave on the bar for the following situations. T

ella [17]

(a) The wavelength of the wave for the fundamental mode is 2.4 m.

(b) The fundamental frequency of the wave is 2,708.33 Hz.

<h3>Wavelength of the wave for fundamental mode</h3>

The wavelength of the wave for the fundamental mode is calculated as follows;

Node to Node, N → N = λ/2

L = λ/2

λ = 2L

λ = 2 x 1.2

λ = 2.4 m

<h3>Fundamental frequency of the wave</h3>

The fundamental frequency of the wave is calculated as follows;

f = v/λ

f₀ = v/2L

f₀ = (6500)/(2 x 1.2)

f₀ = 2,708.33 Hz

The diagram of the wave for the fundamental mode is in the image uploaded.

Learn more about wavelength here: brainly.com/question/10728818

5 0

2 years ago

If you are given time and distance, you can determine power if you know force. watts. energy. joules.

DENIUS [597]

If you are given time and distance, you can determine power if you know force. watts. energy. joules.

Answer is joules.

Power is defined as the rate of doing work. Hence power = work / time then you obtain watts. Work is the product of force and displacement (distance). Hence in formula, w = F x s. In which the S.I unit of work is joule in the product. This is what you have to obtain in order to calculate for power.

4 0

3 years ago

Read 2 more answers

Distance and ___ are really the same quantity. A. length b. direction c. speed d. displacement

Oksi-84 [34.3K]

Answer:

distance and length are the same quantity

4 0

3 years ago