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kari74 [83]
3 years ago
15

as earth rotates about it’s axis, it takes three hours for the united states to pass beneath a point above earth that is station

ary relative to the sun. What is wrong with the following scheme? to travel from washington, D.C. to san francisco shoving very little fuel, simply ascend in a helicopter high over washington, D.C. and wait three hours until san francisco passes below
Physics
1 answer:
pickupchik [31]3 years ago
6 0

interesting question.

how much fuel to hover over one place ?

The Foucault pendulum is a v v v long pendulum which can show the eart's rotation over time if the pend bob motion is tracked and recorded

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When waves superimpose and make bigger amplitudes what form of interference is that
eimsori [14]

Answer:

Constructive Interference

Explanation:

Constructive Interference occurs when two waves superimpose and make bigger amplitudes.

In constructive interference, the crests of one wave fall on the crests of second wave and the amplitudes add up. The amplitude of the resultant wave is equal to sum of the amplitude of the individual waves. Similarly, the trough of first wave falls on the trough of other wave and they superimpose to create the trough of the resultant wave.

For Example, In the attachment, two waves A and B superimpose and demonstrate Constructive interference to create the wave C.

7 0
3 years ago
A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 24 m/
PilotLPTM [1.2K]

Answer:

a) Vf = 27.13 m/s

b) It would have been the same

Explanation:

On the y-axis:

Y=-Vo*sin\theta*t-1/2*g*t^2

-8=-24*sin(21)*t-1/2*10*t^2

Solving for t:

t1 = 0.67s     t2= -2.4s

Discarding the negative value and using the positive one to calculate the velocity:

Vf_y = -Vo*sin\theta-g*t

Vf_y = -15.3m/s

So, the module of the velocity will be:

Vf=\sqrt{(-15.3)^2+(24*cos(21))^2}

Vf=27.13m/s

If you throw it above horizontal, it would go up first, and when it reached the initial height, the velocity would be the same at the throwing instant. And starting then, the movement will be the same.

3 0
3 years ago
Consider a particle on which several forces act, one of which is known to be constant in time: Fi = 3.00 i +4.00 ) N. As a resul
Leviafan [203]

Given that.

F=3•i+4•j

And it from point (0,0)m to (5,6)m

dx=final position - initial position

dx=(5,6)-(0,0)

dx=(5,6)m

dx=5•i +6•j

Work done by the force is give by

W = F•dx

W=F•dx

Note that i•i=j•j=1 and i•j=j•i=0

Then,

W=(3i+4j)•(5i+6j)

Therefore,

W=3i•(5i+6j)+4j•(5i+6j)

W=15i•i+18i•j+20j•i+24j•j

W=15+0+0+24

W=39J

Then the work done by the force is 39 Joules

4 0
3 years ago
Wood has chemical energy which can be used to generate thermal and radiant energy when burned in a fire place which best explain
creativ13 [48]

Answer:

the answer is b:D

Explanation:

5 0
2 years ago
Read 2 more answers
A steam turbine operates with 1.6 MPa and 350°C steam at its inlet and saturated vapor at 30°C at its exit. The mass flow rate o
WINSTONCH [101]

Answer:

638.8kW

Explanation:

The flow rate of the steam m = 22kg/s

The Pressure of the steam at the inlet of the turbine P1 = 1.6MPa

The temperature of the steam at the inlet of the turbine T1 = 350*C

Steam quality at the exit of the turbine x2 = 1.0

The temperature of the steam at the exit of the turbine T2 = 30*C

Power produced = 12,350kW

Assuming the turbine is running on a steady state, hence we neglect the effect of kinetic and potential energy we get:

If you refer to the superheated steam table for the specific enthalpy at a pressure of 1.6MPa and temperature of 350*C, we get

h1 = 3,146kJ/kg

Refer to the steam table for saturated gas at temperature 30*C to get the specific enthalpy value h2 = 2,556.81kJ/kg

The heat that comes out from the turbine can be defined from the balance of energy in the system, and is represented as

Ein - Eout = change in system Energy = 0

Thus Ein = Eout

mh1 = mh2 + Wout + Qout

Qout = m(hi-h2) - Wout

Qout = 22 x (3146-255.6) - 12350

Qout = 638.8kW

3 0
3 years ago
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