The 1 m solutions of C6H1O6 have the highest vapor pressure at a given temperature.
Vapor pressure is defined as the tendency of a liquid to convert into a vapor state. The vapor pressure depends on temperature, surface area, intermolecular forces, and the number of moles of a substance.
The higher the number of moles of particles in solute, the lower the vapor pressure and vice versa.
C6H12O6 has the highest vapor pressure among the given options because it has the lowest number of moles or particles in the solute. The remaining options have more moles of particles in the solute.
If you need to learn more about vapor pressure, click here
brainly.com/question/2510654?referrer=searchResults
#spj4
<span>6.38x10^-2 moles
First, let's determine how many moles of gas particles are in the two-liter container. The molar volume for 1 mole at 25C and 1 atmosphere is 24.465 liters/mole. So
2 L / 24.465 L/mol = 0.081749438 mol
Now air doesn't just consist of nitrogen. It also has oxygen, carbon dioxide, argon, water vapor, etc. and the total number of moles includes all of those other gasses. So let's multiply by the percentage of nitrogen in the atmosphere which is 78%
0.081749438 mol * 0.78 = 0.063764562 mol.
Rounding to 3 significant figures gives 6.38x10^-2 moles</span>
Answer:
D. Shaking a cake [...]
Explanation:
None of the rest are actual physical models representing earthquakes.
Hope that's right! :D
Answer:
It is a chemical change.
Explanation:
When the electricity is off, the filament cools down to its original physical state. This physical process repeats every time the light is turned on and off. However, if the bulb is cracked and air is introduced, the oxygen in the air reacts with the tungsten filament which then undergoes a chemical change.
Answer:
The value of
at 4224 K is 314.23.
Explanation:

Initially
4.97 atm 0
At equilibrium
4.97 - p 2p
At initial stage, the partial pressure of oxygen gas = =4.97 atm
At equilibrium, the partial pressure of oxygen gas = 
So, 4.97 - p = 0.28 atm
p = 4.69 atm
At equilibrium, the partial pressure of O gas = 
The expression of
is given as :


The value of
at 4224 K is 314.23.