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Answer : The value of equilibrium constant for this reaction at 262.0 K is
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = -45.6 kJ = -45600 J
= standard entropy = -125.7 J/K
T = temperature of reaction = 262.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = -12666.6 J
R = gas constant = 8.314 J/K.mol
T = temperature = 262.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 262.0 K is
The appropriate scatter plot that depicts the correct division for using Divide center to draw trend line is the plot D.
<h3>What are Scatter plots?</h3>Scatter plots are used to show how much one variable affects another by plotting data points on a horizontal and vertical axis. Each row in the data table is represented by a marker, the position of which is determined by the values of the columns set on the X and Y axes. Scatter plots are graphs that show the relationship of two variables in a data set. It is a two-dimensional plane or a Cartesian system that represents data points.
In order to draw a trend line correctly, divide the points using the divide center method. The dividing vertical line must be drawn at the midpoint (a position where the number of data points to the left and right of the vertical line is equal).
Only option D has a vertical line dividing the 6 data points into two equal portions when the options are evaluated based on this condition.
The diagram is attached.
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