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Aliun [14]
4 years ago
10

A truck travels due east for a distance of 1.9 km, turns around and goes due west for 8.7 km, and finally turns around again and

travels 3.0 km due east. (a) What is the total distance that the truck travels? km (b) What are the magnitude and direction of the truck's displacement?
Physics
1 answer:
Hatshy [7]4 years ago
8 0

Answer:

a) Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km

b) Total displacement = -1.9km + 8.7km-3.0km=+3.8km

Total displacement = 3.8km due west

Explanation:

a) Total distance travelled is a scalar quantity it is not affected by the direction it's only concerned with the magnitude.

Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km

b) Total displacement is a vector quantity it takes into consideration both magnitude and direction.

Taking west as positive and east as negative.

Total displacement = -1.9km + 8.7km-3.0km = +3.8km

Total displacement = 3.8km due west

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balu736 [363]

Answer:

The voltage across light bulb 1 and light bulb 2 is the the same i.e V

Explanation:

In a parallel circuit, the Voltage is same across all the components of the circuit and the current flowing through each component is added to get the total current across the circuit.

Let us say, the voltage across the circuit is V. The voltage across light bulb 1 and light bulb 2 is the the same i.e V

5 0
3 years ago
A sinusoidally oscillating current I ( t ) with an amplitude of 9.55 A and a frequency of 359 cycles per second is carried by a
UNO [17]

Answer:

P_{avg} = 6.283*10^{-9} \ W

Explanation:

Given that;

I₀ = 9.55 A

f = 359 cycles/s

b = 72.2 cm

c = 32.5 cm

a = 80.2 cm

Using the formula;

\phi = \frac{\mu_o Ic }{2 \pi} In (\frac{b+a}{b})

where;

E= \frac{d \phi}{dt}

E = \frac{\mu_o}{2 \pi}c In (\frac{b+a}{a}) I_o \omega cos \omega t

E_{rms} =   \frac { {\frac{\mu_o \ c}{2 \pi} In (\frac{b+a}{a}) I_o (2 \pi f)}}{\sqrt{2}}

Replacing our values into above equation; we have:

E_{rms} =   \frac { {\frac{4 \pi*10^{-7}*0.325}{2 \pi} In (\frac{72.2+80.2}{80.2}) *9.55 (2 \pi *359)}}{\sqrt{2}}

E_{rms} =   \frac {8.98909588*10^{-4} }{\sqrt{2}}

E_{rms} =   6.356*10^{-4} \ V

Then the P_{avg is calculated as:

P_{avg} = \frac{E^2}{R}

P_{avg} = \frac{(6.356*10^{-4})^2}{64.3}

P_{avg} = 6.283*10^{-9} \ W

6 0
4 years ago
Compare the planets Mars and Saturn. Describe how their common characteristics are similar and Compare the planets Earth and Nep
nordsb [41]

Question no. 1. Compare the planets Mars and Saturn. Describe how their common characteristics are similar:

Answer:  Our solar system is located in the outer spiral arm of the milky way galaxy. our solar system has one sun and nine revolving planets and . namely  

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  2. Venus
  3. Earth
  4. Mars
  5. Jupiter
  6. Saturn
  7. Uranus
  8. Neptune
  9. Pluto (small planet usually refer as dwarf)

Each star has its on moon/moons and has its own characteristics i.e , planet must be a celestial body , must have orbit around sun, have enough mass for self gravity, big enough to have gravity that clear its path from other same size object close to its orbit around sun.

Mars is the fourth from the sun and sixth is the Saturn from the sun in our solar system.

<u>Common in Characteristics of Mars and Saturn:</u>

  • Mars and Saturn both have celestial body.
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  • Mars and Saturn both revolve around the sun in their own orbits.
  • Mars is the second smallest in the solar system while Saturn is second largest in the solar system.
  • Mars and Saturn both have their own moons. Mars has two while Saturn has 83 moons
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Question no. 2. Compare the planets Earth and Neptune. Describe how are they different from each other

Answer:

Earth our home planet is the third from the sun and Neptune on the other hand is the eighth from the sun in the solar system.

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Papessa [141]

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3 years ago
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ANTONII [103]

Answer:

6.71×10⁻⁷ m

Explanation:

Using thin film constructive interference formula as:

<u>2×n×t = m×λ</u>

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n is the refractive index of the refracted surface

t is the thickness of the surface

λ is the wavelength

If m =1

Then,

2×n×t = λ

Given that refractive index pf the oil is 1.22

Thickness of the oil = 275 nm

Also, 1 nm = 10⁻⁹ m

Thickness = 275×10⁻⁹ m

So,

Wavelength is :

<u>λ= 2×n×t = 2× 1.22 × 275×10⁻⁹ m = 6.71×10⁻⁷ m</u>

8 0
4 years ago
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