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Setler79 [48]
2 years ago
6

Empirical formula for C10H8

Chemistry
2 answers:
aliina [53]2 years ago
7 0

Answer:

Explanation:

See picture for explanation

asambeis [7]2 years ago
5 0

Answer:

C5H4

Explanation:

The subscripts in the molecular formula must equal n times the subscripts in the empirical formula (where n is an integer). Both 10 and 8 are divisible by 2, so the empirical formula is C5H4.

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During an endothermic phase change, what happens to the potential energy and the kinetic energy?
antiseptic1488 [7]

During endothermic phase change, the potential energy of the system always increases while the kinetic energy of the system remains constant. The potential energy of the reaction increases because energy is been added to the system from the external environment.

<u>Explanation</u>:

  • Those are three distinct methods for demonstrating a specific energy condition of an object. They don't affect one another.
  • "Potential Energy" is a relative term showing a release of possible energy to the environment. If we accept its pattern as the overall energy state of a compound, at that point, an endothermic phase change would infer an increase in "potential" as energy is being added to the compound by the system.
  • A phase change will display an increase in the kinetic energy at whatever point the compound is transforming from a high density to a low dense phase. The kinetic energy will decrease at whatever point the compound is transforming from a less dense to high dense phase.
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In the following neutralization reaction, which substance is the acid?
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What is the relationship between atomic numbers and atomic radii of elements in group 2a
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For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomas
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Answer:

4.25% is the final concentration of phosphoric acid.

Explanation:

Initial concentration of phosphoric acid = C_1=85\%=0.85

Initial volume of phosphoric acid = V_1=50 mL

Final concentration of phosphoric acid = C_2=?

Final volume of phosphoric acid = V_2=1 L=1000 mL

( 1L = 1000 mL)

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C_2=\frac{C_1times V_1}{V_2}

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4.25% is the final concentration of phosphoric acid.

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