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Setler79 [48]
3 years ago
6

Empirical formula for C10H8

Chemistry
2 answers:
aliina [53]3 years ago
7 0

Answer:

Explanation:

See picture for explanation

asambeis [7]3 years ago
5 0

Answer:

C5H4

Explanation:

The subscripts in the molecular formula must equal n times the subscripts in the empirical formula (where n is an integer). Both 10 and 8 are divisible by 2, so the empirical formula is C5H4.

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Calculate the internal energy (in Joules) of a system that loses 134.8 J that is compressed with a pressure of 5.73 atm from 8.5
Nataly_w [17]

The change in the internal energy of the system is -4511.8 J.

<h3>What is the change in the internal energy?</h3>

We know that according to the first law of thermodynamics, energy can neither be created nor destroyed  but can be transformed from one form to the other.

Now we know that;

ΔE = q + w

ΔE = Change in internal energy

q = heat absorbed or evolved

w = work done

Now we have;

q = - 134.8 J (The system losses heat)

w = PdV

w =  5.73 (1.00 -  8.540)

w = -43.2 Latm or -4377 J

Then we have;

ΔE = - 134.8 J + (-4377 J)

ΔE = -4511.8 J

Learn more about internal energy:brainly.com/question/11278589

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5 0
1 year ago
This green solution of chromium(III) can further be reduced by zinc metal to a blue solution of chromium(II) ions. Write the bal
Contact [7]

Answer:

Half-reactions:

Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻

Net ionic equation:

2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺

Explanation:

The Cr³⁺ is reduced to Cr²⁺:

<h3>Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-</h3>

Zn is oxidized to Zn²⁺:

<h3>Zn → Zn²⁺ + 2e⁻ -Half-reaction 2-</h3>

Twice the reduction of Cr:

2Cr³⁺ + 2e⁻ → 2Cr²⁺

Now this reaction + Oxidation of Zn:

2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻

<h3>2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺ - Net ionic equation</h3>

6 0
3 years ago
When people smoke, carbon monoxide is released into the air. In a room of volume 70 m3, air containing 5% carbon monoxide is int
KonstantinChe [14]

Answer:

\frac {dQ}{dt}=0.0001-\frac {Q}{70}\times 0.002

Explanation:

Given that the volume is 70\ m^3

The air flows (F) at the rate of 0.002\ m^3/min. The concentration of carbon monoxide in the air is 5%.

Let Q be the amount of the carbon monoxide present in the room at time t. then,

\frac {dQ}{dt}=Rate\ of\ Q_{in}-Rate\ of\ Q_{out}

Also,

Rate\ of\ Q_{in}=5\%\ of\ 0.002=0.0001

Rate\ of\ Q_{out}=\frac {Q}{70}\times 0.002

Thus,

\frac {dQ}{dt}=0.0001-\frac {Q}{70}\times 0.002

6 0
4 years ago
The diagram shows an electron shell model of a sodium atom.
jeka94
B. The third shell would be empty so that the eight electrons in the second level would be outermost after the atom loses one electron.
3 0
3 years ago
Read 2 more answers
Physics have been taking the Hippocratic Oath for more than 2,000 years. Among other things, to Serie doctors who take the oath
Sauron [17]

Answer:

Physicians and it is ethical because they promise to help

Explanation:

8 0
3 years ago
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