The correct answer is BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-.
Evaluating be behavior to see :
how it differs from the other Group 2A (2) members.
In this reaction Be behaves like other alkaline earth metals
The complete equation can be given as
BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-
BeCl_2 tends to form a chloro bridged dimer in the vapour state, however at high temperatures of the order of 1200K, this dimer dissociates into the linear monomer.
BeCl_2 has a chain structure in its solid form. Each Be atom in this structure is surrounded by chlorine atoms, two of which are connected by conversion bonds and the remaining two by covalent coordinate connections. This chain structure is displayed.
To know more about BeCl₂(I) + Cl⁻ refer the link:
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Answer:
10. Because they want to, and what they do is none of your buisness.
11. Firefighter-chemicals in fire-stopping have science.
Pharmacist-dealing with drugs and science was used to make them.
Chef-science involved in making food.-
Explanation:
Bruhh these were so easy do it yourself next time, it took me less than a minutte to do.
Answer: Disaccharides
Explanation:
Disaccharides can be defined as the combination of two monosaccharides which combines together to form a disaccharides.
These are formed by the combination of sugars. The process is hydrolysis as it releases water after the reaction is complete.
Two monosachrrides are joined together by the glycosidic linkage. Some common examples are maltose, sucrose and lactose.
<span>PBr5
You started with 0.72 mg of phosphorus and ended up with 10.01 mg of its bromide. So the amount of bromine is 10.01 - 0.72 = 9.29 mg
Now you need to determine the relative number of atoms of each element used.
atomic mass of phosphorus = 30.973762
atomic mass of bromine = 79.904
relative atoms of phosphorus = 0.72 / 30.973762 = 0.023245
relative atoms of bromine = 9.29 / 79.904 = 0.116265
Now you need to look for a simple ratio of integers that closely approximates 0.023245 / 0.116265. First we'll divide the larger by the smaller.
0.116265 / 0.023245 = 5.001597
Given how close the value comes to 5. The empirical formula will be PBr5. So for every atom of phosphorus, you need 5 atoms of bromine.</span>
