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lina2011 [118]
2 years ago
9

True or false: Observing a physical property of a substance will change the substances' identity. I NEED IT NOWWWWW

Chemistry
1 answer:
ale4655 [162]2 years ago
5 0
False

only observing chemical property will change its identity
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Science 10 workbook
Kruka [31]

Answer:

for more details are in the pic

4 0
3 years ago
What is the Law of Definite Composition and how does it apply to pure substances and mixtures?
Lyrx [107]

Answer:

The Law of Definite Proportions ensures that chemical compounds are always created using the same proportions, regardless of the amount of the compound which is being made

5 0
2 years ago
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What is TRUE of a mixture?
jolli1 [7]

Answer:

It retains the properties of the substances that make it up

Explanation:

Mixture show the properties of substances like a mixture of iron filling and sulphur show properties of both

8 0
3 years ago
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The net force on a vehicle that is accelerating at a rate of 1.2 m/s² is 1500 newtons. What is the mass
kotegsom [21]

Answer:

1250kg

Explanation:

Given parameters:

Acceleration  = 1.2m/s²

Force  = 1500N

Unknown:

Mass on the vehicle  = ?

Solution:

According to newton's second law of motion:

  Force  = mass x acceleration

Since mass is the unknown, insert the parameters and solve;

       1500  = mass x 1.2

        mass = \frac{1500}{1.2}   = 1250kg

5 0
2 years ago
Hydrochloric acid (HCl) and sodium hydroxide (NaOH) react to form water and sodium chloride (NaCl). If you have 2.87 g of HCl, 3
wlad13 [49]

Answer:

2.86g

Explanation:

Mass of HCl  = 2.87g

Mass of water  = 3.75g

Mass of NaCl  = 1.98g

Unknown:

Mass of NaOH reacted  = ?

Solution:

  The reaction expression is given as:

           HCl    +   NaOH   →   NaCl   +  H₂O

According to the law of conservation of mass, the mass of reactants and products must be the same.

   Mass of HCl   +   Mass of NaOH  = Mass of NaCl  +  Mass of H₂O

      2.87g + Mass of NaOH  = 1.98g + 3.75g

           Mass of NaOH  = 1.98g + 3.75g - 2.87g  = 2.86g

7 0
3 years ago
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