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3 years ago

Новый источник энергии получивший распространение в годы второй промышленной революции

1 answer:

8 0

1860-х годах, а кульминацией — распространение поточного производства и поточных линий. В 1860—1870-х годах технологическая революция быстро охватила Западную Европу, США, Российскую империю и Японию.

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CH4 + 202 → CO2 + 2H2O

ohaa [14]

It’s a combustion reaction but what are you trying to find?

6 0

2 years ago

Which of the following reactions could be an elementary reaction? 2 NO2(g) + F2(g) → 2NO2F(g) Rate = k[NO2][F2] H2(g) + Br2(g) →

podryga [215]

Answer: The correct answer is $NO(g)+O_2(g)\rightarrow NO_2(g)+O(g);Rate=k[NO][O_2]$

Explanation:

Molecularity of the reaction is defined as the number of atoms, ions or molecules that must colloid with one another simultaneously so as to result into a chemical reaction.

Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.

Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.

For the given reactions:

Equation 1: $2NO_2(g)+F_2(g)\rightarrow 2NO_2F(g);Rate=k[NO_2][F_2]$

Molecularity of the reaction = 2 + 1 = 3

Order of the reaction = 1 + 1 = 2

This is not considered as an elementary reaction.

Equation 2: $H_2(g)+Br_2(g)\rightarrow 2HBr(g);Rate=k[H_2][Br_2]^{1/2}$

Molecularity of the reaction = 1 + 1 = 2

Order of the reaction = $1+\frac{1}{2}=\frac{3}{2}$

This is not considered as an elementary reaction.

Equation 3: $NO(g)+O_2(g)\rightarrow NO_2(g)+O(g);Rate=k[NO][O_2]$

Molecularity of the reaction = 1 + 1 = 2

Order of the reaction = 1 + 1 = 2

This is considered as an elementary reaction.

Equation 4: $NO_2(g)+CO(g)\rightarrow NO(g)+CO_2(g);Rate=k[NO_2]^2$

Molecularity of the reaction = 1 + 1 = 2

Order of the reaction = 2 + 0 = 2

In this equation, the order with respect to each reactant is not equal to its stoichiometric coefficient which is represented in the balanced chemical reaction. Hence, this is not considered as an elementary reaction.

Hence, the correct answer is $NO(g)+O_2(g)\rightarrow NO_2(g)+O(g);Rate=k[NO][O_2]$

3 0

3 years ago

Choose the solvent below that would show the greatest freezing point lowering when used to make a 0.20 m nonelectrolyte solution

tatiyna

Answer : Carbon tetrachloride, $k_f=29.9^oC/m$ will show the greatest freezing point lowering.

Explanation :

For non-electrolyte solution, the formula used for lowering in freezing point is,

$\Delta T_f=k_f\times m$

where,

$\Delta T_f$ = lowering in freezing point

$k_f$ = molal depression constant

m = molality

As per question, the molality is same for all the non-electrolyte solution. So, the lowering in freezing point is depend on the $k_f$ only.

That means the higher the value of $k_f$ , the higher will be the freezing point lowering.

From the given non-electrolyte solutions, the value of $k_f$ of carbon tetrachloride is higher than the other solutions.

Therefore, Carbon tetrachloride, $k_f=29.9^oC/m$ will show the greatest freezing point lowering.

4 0

3 years ago

Which of the following atoms most easily loses an electron Ba Cl Te C P

solong [7]

Ba! It is a metal and wants to lose 2 electrons ASAP

7 0

3 years ago

The shape of the BF3 molecule is best described as

Mars2501 [29]

Answer:

The shape of the BF3 molecule is best described as trigonal planar.

Explanation:

The Lewis Structure for BF3 is like this:

_ _

| F | | F |

\ /

| F |

---

It forms three angles of 120° each. The bonds are in the same planar that's why it is trigonal planar and they are exactly the same.

Boron and Fluorine have 3 covalent bonds, produced by electronic promotion that enables the 2py and 2pz orbitals, leaving an electron to pair in the 2px. So boron will have 3 possible electrons to pair in 2s1, 2px and 2py, remember that electronic configuration for B is 1s2, 2s2, 2p1

By hybridization between the orbitals 2s2 and 2p1, the electrons of F, can joined to make the covalent bond. The new B configuration is 1s2, 2s1, 2px1, 2py1 (these last three, hybrid orbitals)

5 0

3 years ago