Because Any object or substance that is less dense than a fluid will float in that fluid, so hot water rises (floats) in colder water. When fluids are cooled, they contract and therefore become more dense. Any object or substance that is more dense than a fluid will sink in that fluid, so cold water sinks in warmer water
The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
CALCULATE INITIAL VELOCITY:
The initial velocity of the car can be calculated by using one of the equation of motion as follows:
V = u + at
Where;
- V = final velocity (m/s)
- u = initial velocity (m/s)
- a = acceleration due to gravity (m/s²)
- t = time (s)
According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:
u = v - at
u = 27 - 3(5)
u = 27 - 15
u = 12m/s.
Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
Learn more about motion at: brainly.com/question/974124
Answer:
It's called an ampere!
Explanation:
The SI unit of electric current is the ampere, which is the flow of electric charge across a surface at the rate of one coulomb per second. The ampere (symbol: A) is an SI base unit Electric current is measured using a device called an ammeter.
Hope this helps :)
Answer:
The maximum amount of work is 
Explanation:
From the question we are told that
The temperature of the environment is 
The volume of container A is 
Initially the number of moles is 
The volume of container B is 
At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as
![W = P_A V_A ln[ \frac{V_B}{V_A} ]](https://tex.z-dn.net/?f=W%20%3D%20%20P_A%20V_A%20%20ln%5B%20%5Cfrac%7BV_B%7D%7BV_A%7D%20%5D)
Now from the Ideal gas law
So substituting for 
in the equation above
![W = nRT ln [\frac{V_B}{V_A} ]](https://tex.z-dn.net/?f=W%20%3D%20%20nRT%20ln%20%5B%5Cfrac%7BV_B%7D%7BV_A%7D%20%5D)
Where R is the gas constant with a values of 
Substituting values we have that
![W = 1.2 * (8.314) * (280) * ln [\frac{3.5}{2} ]](https://tex.z-dn.net/?f=W%20%3D%201.2%20%2A%20%288.314%29%20%2A%20%28280%29%20%2A%20ln%20%5B%5Cfrac%7B3.5%7D%7B2%7D%20%5D)
<span>Porous material has many spaces that can hold(store) groundwater.</span>
