<u>Answer:</u>
The force F applied to the handle = 330.03 N
<u>Explanation:</u>
The force can be resolved in to two, horizontal component and vertical component. If θ is the angle between horizontal and applied force we have
Horizontal component of force = F cos θ
Vertical component of force = F sin θ
In this problem normal force exerted on the suitcase is 160 N, that is vertical component of force = 160 N and angle θ = 29⁰.
So, F sin 29 = 160
F = 330.03 N
The force F applied to the handle = 330.03 N
Answer:
See Explanation
Explanation:
Solving (4): 0.84554 as a fraction
The above number is to 5 decimal places, so the fraction equivalent is:
Divide numerator and denominator by 2
Solving (5):
The midpoint, M is calculated as follows:
Where
The distance, D is calculated using:
Solving (1): The expression for f(x) is not clear. So, I'll make use of:
Substitute each value of the domain in
The range is:
Solving (2):
Shape: Open Cylinder
The surface area is calculated as:
Solving (3):
The value of a is not clear. So, I'll assume that a is a
Given that
Find
Substitute 3a for b
Absolute value of 4a is 4a. So,
Solving (9):
Given
--- Principal
--- Rate
--- Time in years
The amount (A) is calculated as follows:
Hence, the amount at the end of 2 years is:
Answer:
Explanation:
mass of car, m = 1000 kg
initial velocity, u = 20 m/s
final velocity, v = 0 m/s
distance, s = 120 m
Let a be the acceleration of motion
use third equation of motion
v² = u² + 2 as
0 = 20 x 20 + 2 x a x 120
a = - 1.67 m/s²
Let F be the force
Force, F mass x acceleration
F = - 1000 x 1.67
F = - 1666.67 N
The direction of force is towards south and the magnitude of force is 1666.67 N.
Answer:
999.23 km/h
Explanation:
We can use the formula for average speed as "Distance divided time" to solve the problem.
Let's start by writing the time in hours: 4 h and 20 min is the same as 4 hours + 1/3 of an hour = 13/3 of an hour
Now we use this number in the quotient for average speed:
Average speed = 4330 km / (13/3) h = 12990 / 30 km/h = 999.23 km/h