Answer:
v = 0.999981c m/s
Explanation:
Using the time dilation equation
T = stationary time = 100 years
T₀ = 11/12 years = 0.917 years
v = speed of travel in the space = ?
c = speed of light = 3 * 10⁸ m/s
v = 299987395.57 m/s
v = 2.99 * 10⁸ m/s
v = 0.999981c m/s
Answer:
b) 3.72m/s²
c) 9.33*10^5
d) 9.33*10^5
e) 11.85 hrs
Explanation:
a) to confirm that gEarth is about 98 m/s².
Let's use the formula:
= 9.78 m/s²
=> 9.8m/s²
b) Given:
r = 2106 miles
=3.72 m/s²
c) we use:
d) Let's take the force of gravitybon earth due to satellite as our answer in (c) because the Earth's gravitational force on a GPS satellite and the force of gravity on a GPS satellite on earth are equal and opposite (two mutual forces).
e) In a circular motion,
Gravitional force = Centripetal force.
Solving for v, we have
v = 3886m/s
Therefore,
v = 2πR/T
Solving for T, we have:
T = 42650seconds
Convert T to hours
T = 42650/60*60
T = 11.86hrs
Answer:
The time required by object to achieve velocity 58 m/s is 5.918 second.
Given:
acceleration = 9.8
Initial velocity = 0 m/s
final velocity = 58 m/s
To find:
Time required by object = ?
Formula used:
According to first equation of motion is given by,
v = u + at
Where, v = final velocity
u = initial velocity = 0 (Given The particle is at rest initially)
a = acceleration
t = time
Solution:
According to first equation of motion is given by,
v = u + at
Where, v = final velocity
u = initial velocity = 0 (Given The particle is at rest initially)
a = acceleration
t = time
58 = 0 + 9.8 (t)
t =
t = 5.918 s
The time required by object to achieve velocity 58 m/s is 5.918 second.