The answer is B.
plz mark me as brainliest. i really need it.
Answer:
0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).
Explanation:
<em>d = m/V,</em>
where, d is the density of the material (g/cm³).
m is the mass of the material (m = 28 g).
V is the volume of the material (V = 63.0 cm³).
<em>∴ d = m/V </em>= (28 g)/(63.0 cm³) = <em>0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).</em>
<h3>
Answer:</h3>
5.89%
<h3>
Explanation:</h3>
We are given;
- Mass of the solute, LiOH as 40.1 g
- Mass of the solvent, H₂O as 681 g
We are required to calculate the mass percent composition of solution;
- But; How do we calculate the mass percent composition of a solution?
- We use the formula;
- Mass composition of a solution = (Mass of solute/mass of solution) 100%
Mass Percent = (40.1 g/681 g)× 100%
= 5.888 %
= 5.89%
Therefore, the mass percent composition of the solution is 5.89%
Answer:
The answer to your question is: HCl = 58.44 g
Explanation:
To solve this problem, we must remember the law of conservation of mass that says that, matter cannot be created or destroyed, only changes its form.
That means that, the mass of the reactants must be equal to the mass of the products.
Process
Sodium (Na) + Chlorine (Cl) ⇒ Sodium chloride (HCl)
22.99 g 35.45 g x
22.99 + 35.45 = HCl
HCl = 58.44 g