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alexdok [17]
4 years ago
12

Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 VAl3++3e−→Al;E∘=−1

.66 V Ag++e−→Ag;E∘=0.799 V
Chemistry
1 answer:
lana66690 [7]4 years ago
5 0

Answer:

2.459 V

Explanation:

If we look at the data we have from the question closely, we will discover that aluminum has a very negative reduction potential. Recall that very negative reduction potentials are associated with strong reducing agents.

Similarly, silver has a positive reduction potential signifying that it is an oxidizing agent. Since the reducing agent is oxidized in a redox reaction and the oxidizing agent is reduced.

Hence;

E°cell= E°reduction process - E°oxidation process

E°cell= 0.799 -(-1.66)

E°cell= 2.459 V

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If 31.6 g of KMnO4 is dissolved in enough water to give 160 mL of solution, what is the molarity?
Zina [86]

Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

5 0
3 years ago
Which of the following is a strong base
Anna [14]
Please list the answers so I can answer this question. 
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3 years ago
]\ \textless \ br /\ \textgreater \ \huge \boxed{ \red{φµεรƭเσɳ -}} \ \textless \ br /\ \textgreater \ ​ \ \textless \ br /\ \te
azamat

Answer:

Nitrogen fixation is a chemical process by which molecular nitrogen in the air is converted into ammonia or related nitrogenous compounds in soil or aquatic systems. Atmospheric nitrogen is molecular dinitrogen, a relatively nonreactive molecule that is metabolically useless to all but a few microorganisms.

Explanation:

6 0
3 years ago
Read 2 more answers
A chemist adds of a zinc nitrate solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has a
Ray Of Light [21]

Answer:

5.3 × 10⁻³ kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution. The moles of zinc nitrate are:

0.1350 L × 0.21 mol/L = 2.8 × 10⁻² mol

The molar mass of zinc nitrate is 189.36 g/mol. The mass corresponding to 2.8 × 10⁻² moles is:

2.8 × 10⁻² mol × 189.36 g/mol = 5.3 g

1 kilogram is equal to 1000 grams. Then,

5.3 g × (1 kg/1000 g) = 5.3 × 10⁻³ kg

8 0
3 years ago
12. In which equilibrium system will an increase in pressure cause a shift to the left?
son4ous [18]

D is the answer cause two h20 + o2(g)

3 0
3 years ago
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