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alexdok [17]
4 years ago
12

Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 VAl3++3e−→Al;E∘=−1

.66 V Ag++e−→Ag;E∘=0.799 V
Chemistry
1 answer:
lana66690 [7]4 years ago
5 0

Answer:

2.459 V

Explanation:

If we look at the data we have from the question closely, we will discover that aluminum has a very negative reduction potential. Recall that very negative reduction potentials are associated with strong reducing agents.

Similarly, silver has a positive reduction potential signifying that it is an oxidizing agent. Since the reducing agent is oxidized in a redox reaction and the oxidizing agent is reduced.

Hence;

E°cell= E°reduction process - E°oxidation process

E°cell= 0.799 -(-1.66)

E°cell= 2.459 V

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irga5000 [103]
The answer is B.

plz mark me as brainliest. i really need it.
8 0
4 years ago
A material has a volume of 63.0 cm3 and a mass of 28 grams.  What is the density of the material in g/cm3 to the correct number
dimaraw [331]

Answer:

0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

Explanation:

  • Knowing that:

<em>d = m/V,</em>

where, d is the density of the material (g/cm³).

m is the mass of the material (m = 28 g).

V is the volume of the material (V = 63.0 cm³).

<em>∴ d = m/V </em>= (28 g)/(63.0 cm³) = <em>0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).</em>

7 0
3 years ago
Determine the mass percent composition of a solution made by dissolving 40.1g of LiOH in 681g of H2O
Lapatulllka [165]
<h3>Answer:</h3>

5.89%

<h3>Explanation:</h3>

We are given;

  • Mass of the solute, LiOH as 40.1 g
  • Mass of the solvent, H₂O as 681 g

We are required to calculate the mass percent composition of solution;

  • But; How do we calculate the mass percent composition of a solution?
  • We use the formula;
  • Mass composition of a solution = (Mass of solute/mass of solution) 100%
  • Therefore;

Mass Percent = (40.1 g/681 g)× 100%

                       = 5.888 %

                       = 5.89%

Therefore, the mass percent composition of the solution is 5.89%

7 0
3 years ago
54. Copper(I) sulfide is formed when copper and sulfur are
jasenka [17]

Answer:

159g

Explanation:

5 0
3 years ago
If 22.99 g of sodium and 35.45 g of chlorine fully react, how much sodium chloride forms?​
matrenka [14]

Answer:

The answer to your question is: HCl = 58.44 g

Explanation:

To solve this problem, we must remember the law of conservation of mass that says that, matter cannot be created or destroyed, only changes its form.

That means that, the mass of the reactants must be equal to the mass of the products.

               Process

                    Sodium (Na)  +    Chlorine (Cl)   ⇒     Sodium chloride (HCl)

                         22.99 g              35.45 g                            x

              22.99 + 35.45 = HCl

              HCl = 58.44 g

3 0
3 years ago
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