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Vladimir79 [104]
3 years ago
12

Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle

r sphere. If the electric field just outside of the smaller sphere is E0, then the electric field just outside of the larger sphere is:
a. E0
b. 1/3 E0
c. 9 E0
d. 3 E0
e. 1/9 E0
Physics
1 answer:
Mrac [35]3 years ago
3 0

Answer:

Explanation:

Let the smaller sphere have a radius of  R

Electric field on its surface( just outside the sphere)  (E₀) = k Q / R²

Electric field on the surface of larger sphere

(E) = k Q / (3R)²

= k Q / 9R²

= E₀ / 9

So option e is correct.

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Mrs. Paul and Dr. Mykannen ride a tandem bike on the beach. They ride along the beach for about 455 meters. Their final velocity
algol [13]

Answer:

Time = 80.91 seconds

Explanation:

Given the following data;

Velocity = 5.50 m/s.

Distance = 445 meters

To find the time;

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

Velocity = \frac{distance}{time}

Substituting into the formula, we have;

5.5 = 445/time

Time = 445/5.5

Time = 80.91 seconds

5 0
3 years ago
For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ
slava [35]

Explanation:

First we will convert the given mass from lb to kg as follows.

        157 lb = 157 lb \times \frac{1 kg}{2.2046 lb}

                   = 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

         180 \frac{mg}{kg} \times 71.215 kg

         = 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

      0.65% (w/w) = \frac{0.65 g}{100 g}

                           = \frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}

                           = \frac{0.65 g}{100 ml}

Therefore, calculate the volume which contains the amount of caffeine as follows.

   12818.7 mg = 12.8187 g = \frac{12.8187 g}{\frac{0.65 g}{100 ml}}

                       = 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

5 0
3 years ago
If the wavelength is changed to λ/2, does the central spot remain bright, does the central spot become dark, or do the fringes d
omeli [17]

Answer:The central spot becomes Dark

Explanation: it become dark because as the wavelength reduces,the velocity in the detector decreases, this time by 90degrees

4 0
4 years ago
If an acid is splashed on your skin , wash at once with
Blizzard [7]

water, if this were to occur u would want to immediately wash it with well water.


Reason: Strong bases react with the oils in your skin to produce a soapy feeling layer. Rinse until well after that feeling is gone.

6 0
4 years ago
An ideal gas initially is allowed to expand isothermally until its volume of 1.6 L and pressure is 5 kPa, undergoes isothermal e
Marina86 [1]

(a) The work done by the gas during the isothermal expansion is -25.6 J.

(b) The heat added to the gas during this process is 25.6 J.

<h3>Net work done by the ideal gas against the external pressure</h3>

The net work done by the ideal gas in the isothermal expansion is calculated as follows;

W(net) = ΔP x ΔV

W(net) = ( 1 kPa - 5 kPa) x (8L - 1.6 L)

W(net) = -25.6 kPa.L

W(net) = -25.6 J

<h3>Head added to the gas</h3>

The heat added to the gas is calculated as follows;

W = -Q

-25.6 J = -Q

Q = 25.6 J

Learn more about Isothermal expansion here: brainly.com/question/17192821

7 0
2 years ago
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