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KiRa [710]
3 years ago
15

What is a smash shot? (BADMINTON)

Physics
1 answer:
zaharov [31]3 years ago
5 0
The smash shot in badminton is considered one of the most powerful kind of shot that can tilt the score in your favour. This shot can only be excited when the shuttle is high in the air. The reason behind that is because from a high elevation point, the shuttle is smashed downward over the net into the opponent's court. There is almost no defence against such a shot because it is slammed so quickly and is at such a downward angle that it is difficult for the opponent to receive it.
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A beam of light has a wavelength of 650 nm in vacuum. (a) What is the speed of this light in a liquid whose index of refraction
Lady_Fox [76]

Answer:

The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

Explanation:

Given that,

Wavelength = 650 nm

Index refraction = 1.47

(a). We need to calculate the speed

Using formula of speed

n = \dfrac{c}{v}

Where, n = refraction index

c = speed of light in vacuum

v = speed of light in medium

Put the value into the formula

1.47=\dfrac{3\times10^{8}}{v}

v=\dfrac{3\times10^{8}}{1.47}

v= 2.04\times10^{8}\ m/s

(b). We need to calculate the wavelength

Using formula of wavelength

n=\dfrac{\lambda_{0}}{\lambda}

\lambda=\dfrac{\lambda_{0}}{n}

Where, \lambda_{0} = wavelength in vacuum

\lambda = wavelength in medium

Put the value into the formula

\lambda=\dfrac{650\times10^{-9}}{1.47}

\lambda=442\times10^{-9}\ m

Hence, The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

3 0
3 years ago
What is the formula for mechanical advantage?
Sladkaya [172]

Answer:

A. MA=force output/force input

Explanation:

mechanical advantage is the ratio of the load to the effort

8 0
3 years ago
Read 2 more answers
Which one of the following temperatures (in °C) is equivalent to 294 K?
vaieri [72.5K]

Answer:

21

Explanation: its actually 20.85 but i guess they round to 21

5 0
2 years ago
D. What is the net force on the bowling ball rolling lane
3241004551 [841]

Answer:

Friction

Explanation:

3 0
2 years ago
2. A Se lanza un electrón con rapidez inicial v0 = 1.60×106 m/s hacia el interior de un campo uniforme entre las placas paralela
Vanyuwa [196]

Answer:

A)     E = 145.6 N / C , B)  y= 2,8 10-7 m with a downward direction

C) he shape of the trajectory of the two particles is to simulate a parabola,

D)     F_{e} /F_{g} = 10³⁴

Explanation:

A) For this exercise we use Newton's second law to find the acceleration of the electron, where the force is electric

           F = m a  

           - e E = m a

          a = - e E / m

with the field directed downward, the acceleration is in the vertical upward direction.

We look for how much the electron moves with kinematics, in the x direction there is no acceleration,

x axis (parallel to plates)

           x = v₀ t

           t = x / v₀

y axis (perpendicular to plates)

          y = y₀ + v_{oy} t + ½ a t²

Let's take the zero of the system in the middle of the plates y₀ = 0, also the initial vertical velocity is zero (v_{oy} = 0) the width of the plate is known

          y = ½ a t²

we substitute

         y = ½ (e E /m)  (x / v₀)²

         y = ½ e x2 /m v₀²   E

we look for the electric field

        E = 2 m y v₀² / e x²

where to use this expression the length and width of the condenser must be known, suppose that the length is x = l = 1 cm = 1 10⁻² m and the width is y = 0.5 mm = 0.5 10⁻³ m

let's calculate

         E = 2  9.1 10⁻³¹ 0.5 10⁻³ (1.6 10⁶)² / (1.6 10⁻¹⁹ (1 10⁻²)²)

         E = 145.6 N / C

B) The electron is exchanged for a proton

Let's look for the vertical displacement, in this case as the proton has a positive charge it moves towards the bottom of the plates

          y = ½ e x² / m v₀² E

          y = ½ 1.6 10⁻¹⁹ 1 10⁻⁴ / (1.67 10⁻²⁷ (1.6 10⁶)²   145.6

          y = 28.4375 10⁻⁸ m

since the distance between the plates is 0.5 10-3 m, the proton passes the condensate because its deflection is very small

In summary, its displacement is y= 2,8 10-7 m and with a downward direction (the same direction of the electric field)

C) The shape of the trajectory of the two particles is to simulate a parabola, but one for having a negative charge (electron) the force is upwards and the other for having a positive charge (proton) the trajectory is downwards

D) The force of gravity

           F_{g} = G m M / R²

electron

          Between the electron and the positive charges of the conducting plate

           F_{g}= 6.67 10⁻¹¹ 1.67 10⁻²⁷ 9.1 10⁻³¹ / (0.5 10⁻³)²

           F_{g} = 4.1 10⁻⁵¹ N

           

electric force

           F_{e} = -e E

           F_{e} = - 1.6 10⁻¹⁹ 145.6

           F_{e} = 2.3 10⁻¹⁷ N

let's look for the reason between these two forces

         F_{e} / F_{g} = 2.3 10⁻¹⁷ / 4.1 10⁻⁵¹

          F_{e} /F_{g} = 10³⁴

We see that the electric force is many orders of magnitude higher than the gravitational force.

5 0
3 years ago
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