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3 years ago

What is a smash shot? (BADMINTON)

1 answer:

5 0

The smash shot in badminton is considered one of the most powerful kind of shot that can tilt the score in your favour. This shot can only be excited when the shuttle is high in the air. The reason behind that is because from a high elevation point, the shuttle is smashed downward over the net into the opponent's court. There is almost no defence against such a shot because it is slammed so quickly and is at such a downward angle that it is difficult for the opponent to receive it.

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Which of the following statements are true concerning electromagnetic induction? Check all that apply. It is possible to induce

Sladkaya [172]

Answer:

a,b,c and d.

Explanation:

Of the following statements the correct are:

a) It is possible to induce a current in a closed loop of wire located in a uniform magnetic field by either increasing or decreasing the area enclosed by the loop.

b) It is possible to induce a current in a closed loop of wire without the aid of a power supply or battery.

d) It is possible to induce a current in a closed loop of wire by change the orientation of a magnetic field enclosed by the wire.

e) It is possible to induce a current in a closed loop of wire by changing the strength of a magnetic field enclosed by the wire.

8 0

3 years ago

Read 2 more answers

Parallax of the stars is created by

k0ka [10]

Parallax of the stars is created by :
B. Different locations of Earth in its orbit
Parallax refer to the position of an object (in this case, a star) that will look different if we view it from different positions

hope this helps

4 0

3 years ago

Read 2 more answers

When the input voltages of a difference amplifier are 5.1 v and 6.4 v, the output voltage is 64.7 v. The inputs are changed to 4

daser333 [38]

Answer:

a) Differential mode gain = 48

b) Common mode gain = 0.4

c) CMRR = 120

Explanation:

The output of a difference amplifier is related to the input by the equation:

$V_{0} = A_{1} V_{1} + A_{2} V_{2} \\$

When V₁ = 6.4 V, V₂ = 5.1 V and V₀ = 64.7 V, the equation becomes

6.4 A₁ + 5.1 A₂ = 64.7.....................(1)

When V₁ = 5.6 V, V₂ = 4.9 V and V₀ = 35.7 V, the equation becomes

5.6 A₁ + 4.9 A₂ = 35.7.....................(2)

Multiply equation (1) by 5.6 and (2) by 6.4

35.84 A₁ + 28.56A₂ = 362.32.....................(3)

35.84 A₁ + 31.36 A₂ = 228.48....................................(4)

Subtract equation (3) from (4)

2.8 A₂ = -133.84

A₂ = -133.84/2.8

A₂ = -47.8

Put the value of A₂ into equation (1)

6.4 A₁ + 5.1 (-47.8) = 64.7

6.4 A₁ = 64.7 + 243.78

A₁ = 308.48/6.4

A₁ = 48.2

a) Common mode gain = A₁ + A₂ = 48.2 + (-47.8)

Common mode gain = 0.4

b) Differential mode gain = (A₁ -A₂)/2

Differential mode gain = (48.2 - (-47.8))/2

Differential mode gain = 96/2

Differential mode gain = 48

c) Common Mode Rejection Ratio (CMRR)

$CMRR = |\frac{Differential Mode Gain}{Common Mode Gain} |$

$CMRR = |\frac{48}{0.4} |\\CMRR = 120$

4 0

3 years ago

Got an F in Physical Science. HELP ME PLZZZ

Dmitriy789 [7]

i know can you plzz help me with this question im sorry i didt answer your question i just need hel.

7 0

3 years ago

How are stars formed and classified?

Romashka-Z-Leto [24]

Stars form from an accumulation of gas and dust, which collapses due to gravity and starts to form stars. Stars are typically classified by their spectrum in what is known as the Morgan-Keenan or MK system.

6 0

3 years ago