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lukranit [14]
2 years ago
9

Light passes through a pair of very thin parallel slits. The resulting interference pattern is viewed far from the slits at vari

ous angles θ relative to the centerline coming outward from the midpoint between the slits. The central bright fringe is at θ=0∘. If the central bright fringe has intensity I0, what is the intensity of the next bright fringe on either side of it?
Physics
1 answer:
butalik [34]2 years ago
4 0

Answer:

Intensity of the next bright fringe will remain same.

Explanation:

The question is based on Young's double slit experiment, since its about bright fringe, the interference here is constructive.

Young's condition for constructive interference is given by:

dsin\theta = n\lambda

where,

d = slits distance from eachother or width of the slits

\lambda = wavelength

n = interferance order

Also, we know that in Young's experiment, the fringe intensity is given by:

I' = 4Icos^{2}\phi

where,

\phi = phase difference

Therefore, in absence of phase difference i.e., \phi = 0, the intensity of the next bright fringe will not change and it will remain same.

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A 0.5 kg mass on a spring undergoes simple harmonic motion with a total mechanical energy of 12 J. If the oscillation amplitude
Darya [45]

Answer:

The frequency of the oscillation is 2.45 Hz.

Explanation:

Given;

mass of the spring, m = 0.5 kg

total mechanical energy of the spring, E = 12 J

Determine the spring constant, k as follows;

E = ¹/₂kA²

kA² = 2E

k = (2E) / (A²)

k = (2 x 12) / (0.45²)

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Determine the angular frequency, ω;

\omega = \sqrt{\frac{k}{m} } \\\\\omega =  \sqrt{\frac{118.519}{0.5} } \\\\\omega = 15.396 \ rad/s

Determine the frequency of the oscillation;

ω = 2πf

f = (ω) / (2π)

f = (15.396) / (2π)

f = 2.45 Hz

Therefore, the frequency of the oscillation is 2.45 Hz.

8 0
2 years ago
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Answer:

<h2>70,000 kg.m/s</h2>

Explanation:

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