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lukranit [14]
3 years ago
9

Light passes through a pair of very thin parallel slits. The resulting interference pattern is viewed far from the slits at vari

ous angles θ relative to the centerline coming outward from the midpoint between the slits. The central bright fringe is at θ=0∘. If the central bright fringe has intensity I0, what is the intensity of the next bright fringe on either side of it?
Physics
1 answer:
butalik [34]3 years ago
4 0

Answer:

Intensity of the next bright fringe will remain same.

Explanation:

The question is based on Young's double slit experiment, since its about bright fringe, the interference here is constructive.

Young's condition for constructive interference is given by:

dsin\theta = n\lambda

where,

d = slits distance from eachother or width of the slits

\lambda = wavelength

n = interferance order

Also, we know that in Young's experiment, the fringe intensity is given by:

I' = 4Icos^{2}\phi

where,

\phi = phase difference

Therefore, in absence of phase difference i.e., \phi = 0, the intensity of the next bright fringe will not change and it will remain same.

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The force of repulsion that two like charges exert on each other 5N. what will be if the distance between the charge is decrease
GalinKa [24]

The new force becomes One Ninth (1/9) of the original force.

The force between two point charges (let's say \mathrm{Q} 1$ and $\mathrm{Q} 2$ ) is given by the following formula:

Force $=k \times Q 1 \times Q 2$divided by ( $r$ squared)

Here r is the distance.

If we multiply r by three then after squaring it will become $9 \times r$ squared.

Let's rewrite the formula and call it new Force:

New Force =\mathrm{K} \times \mathrm{Q} 1 \times \mathrm{Q} 2 divided by $(9 \times \mathrm{r}$ squared )

Now just separate the 9 :

New Force $=1 / 9(\mathrm{~K} \times \mathrm{Q} 1 \times \mathrm{Q} 2$divided by $(\mathrm{r}$ Squared ))

New Force $=1 / 9$ (Force)

So turns out that the new force becomes One Ninth (1/9) of the original force.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to define force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Learn more about force brainly.com/question/13191643

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6 0
2 years ago
Determine the work done by the constant force. The locomotive of a freight train pulls its cars with a constant force of 15 tons
Digiron [165]

Answer:

5.92×10⁷ J

Explanation:

We'll begin by converting 15 tons to Newton. This can be obtained as follow:

1 ton = 9806.65 N

Therefore,

15 ton = 15 ton × 9806.65 N / 1 ton

15 ton = 147099.75 N

Next, we shall convert one-quarter (¼) or 0.25 mile to metre. This can be obtained as follow:

100 mi = 160934 m

0.25 mi = 0.25 mi × 160934 / 100 mi

0.25 mi = 402.335 m

Finally, we shall determine the Workdone. This can be obtained as follow:

Force (F) = 147099.75 N

Distance (d) = 402.335 m

Workdone (Wd) =?

Wd = F × d

Wd = 147099.75 × 402.335

Wd = 5.92×10⁷ J

Thus, the Workdone is 5.92×10⁷ J

5 0
3 years ago
PLEASE HELP ME ASAP!!!
maks197457 [2]
Answer:

<span>Plants that have been buried</span>

Explanation :

According to the provided graph it is showing that the plant dies and buried before  microbes which make them decay , then heat and pressure in Earth's crust for millions of years which can turn into coal,gas, or oil which then is extracted and burnt to create carbon dioxide in which a plant takes it in and the process repeats
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3 years ago
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How is electron movement related to the bonding in sodium chloride?
irina1246 [14]
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8 0
3 years ago
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A stationary block resting on the ground is pulled up with a tension force of 100N, but does not leave the ground.
tekilochka [14]

Answer:

The normal force the ground exerts on the block, F = -300 N

Explanation:

Given data,

The block pulled up with a tension force, T = 100 N

The weight of the block, W = 300 N

The weight of the block is due to the force of attraction of gravitation.

The surface exerts a force that is equal and opposite to the force acting on the block due to gravitation.

The weight of the block,

                                  W = mg

                                          300 N

The normal force the ground exerts on the block,

                                  F = - mg

                                    = - 300 N

Hence, the normal force the ground exerts on the block, F = -300 N

6 0
3 years ago
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