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lukranit [14]
3 years ago
9

Light passes through a pair of very thin parallel slits. The resulting interference pattern is viewed far from the slits at vari

ous angles θ relative to the centerline coming outward from the midpoint between the slits. The central bright fringe is at θ=0∘. If the central bright fringe has intensity I0, what is the intensity of the next bright fringe on either side of it?
Physics
1 answer:
butalik [34]3 years ago
4 0

Answer:

Intensity of the next bright fringe will remain same.

Explanation:

The question is based on Young's double slit experiment, since its about bright fringe, the interference here is constructive.

Young's condition for constructive interference is given by:

dsin\theta = n\lambda

where,

d = slits distance from eachother or width of the slits

\lambda = wavelength

n = interferance order

Also, we know that in Young's experiment, the fringe intensity is given by:

I' = 4Icos^{2}\phi

where,

\phi = phase difference

Therefore, in absence of phase difference i.e., \phi = 0, the intensity of the next bright fringe will not change and it will remain same.

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Answer:

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Explanation:

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Use this equation:

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Rearranging the equation to find the specific heat (c) you get this:

c = (( mw c + mAl cAl )  ΔT') / (mΔT)

c = (( 0.285 (4186) + (0.15)(900)) (32 -25.1)) / ((0.125) (95 - 32))

c = 1163.34 J/kg.°C

7 0
3 years ago
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A gas occupies a volume of 20 cubic meters at 9,000 pascals. If the pressure is lowered to 5,000 pascals, what volume will the g
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Volume and pressure are inversely proportional magnitudes, so we can write:

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2 years ago
Waves transport
Brilliant_brown [7]

Answer:

d)energy

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Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

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You place a 55.0 kg box on a track that makes an angle of 28.0 degrees with the horizontal. The coefficient of static friction b
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Answer:

\theta=34 \textdegree

Explanation:

From the question we are told that:

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Generally, the equation for Newtons second Law is mathematically given by

For

\sum_y=0

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for

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F_{s}=mgsin\theta

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F_{s}=0.68*55*9.8*cos 28

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Therefore

\alpha mgcos \theta=mg sin \theta

\theta=tan^{-1}(0.68)

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6 0
2 years ago
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Answer:

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