Answer:
0.0133A
Explanation:
Since we have two sections, for the Inductor region there would be a current
. In the case of resistance 2, it will cross a current
Defined this we proceed to obtain our equations,
For
,
![\frac{di_1}{dt}+i_1R_1 = V](https://tex.z-dn.net/?f=%5Cfrac%7Bdi_1%7D%7Bdt%7D%2Bi_1R_1%20%3D%20V)
![I_1 = \frac{V}{R_1} (1-e^{-\frac{R_1t}{L}})](https://tex.z-dn.net/?f=I_1%20%3D%20%5Cfrac%7BV%7D%7BR_1%7D%20%281-e%5E%7B-%5Cfrac%7BR_1t%7D%7BL%7D%7D%29)
For
,
![I_2R_2 =V](https://tex.z-dn.net/?f=I_2R_2%20%3DV)
![I_2 = \frac{V}{R_2}](https://tex.z-dn.net/?f=I_2%20%3D%20%5Cfrac%7BV%7D%7BR_2%7D)
The current in the entire battery is equivalent to,
![i_t = I_1+I_2](https://tex.z-dn.net/?f=i_t%20%3D%20I_1%2BI_2)
![i_t = \frac{V}{R_2}+\frac{V}{R_1} (1-e^{-\frac{R_1t}{L}})](https://tex.z-dn.net/?f=i_t%20%3D%20%5Cfrac%7BV%7D%7BR_2%7D%2B%5Cfrac%7BV%7D%7BR_1%7D%20%281-e%5E%7B-%5Cfrac%7BR_1t%7D%7BL%7D%7D%29)
Our values are,
![V=1V](https://tex.z-dn.net/?f=V%3D1V)
![R_1 = 95\Omega](https://tex.z-dn.net/?f=R_1%20%3D%2095%5COmega)
![L= 1.5*10^{-2}H](https://tex.z-dn.net/?f=L%3D%201.5%2A10%5E%7B-2%7DH)
![R_2 =360\Omega](https://tex.z-dn.net/?f=R_2%20%3D360%5COmega)
Replacing in the current for t= 0.4m/s
![i=\frac{1}{360}+\frac{1}{95}(1-e^{-\frac{95*0.4}{1.5*10^{-2}}})](https://tex.z-dn.net/?f=i%3D%5Cfrac%7B1%7D%7B360%7D%2B%5Cfrac%7B1%7D%7B95%7D%281-e%5E%7B-%5Cfrac%7B95%2A0.4%7D%7B1.5%2A10%5E%7B-2%7D%7D%7D%29)
![i= 0.0133A](https://tex.z-dn.net/?f=i%3D%200.0133A)
![i_1 = 0.01052A](https://tex.z-dn.net/?f=i_1%20%3D%200.01052A)
Mechanical digestion is chewing, and chemical digestion is the saliva in your mouth breaking down food.
Answer: the water level would rise since the pebble displaces minimal water compared to the boat.
Explanation:..........
Answer:
t = 8.45 sec
car distance d = 132.09 m
bike distance d = 157.08 m
Explanation:
GIVEN :
motorcycle is 25 m behind the car , therefore distance need to covered by bike to overtake car is 25+ d, when car reache distance d at time t
for car
by equation of motion
![d = ut + \frac{1}{2}at^2](https://tex.z-dn.net/?f=d%20%20%3D%20ut%20%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2)
u = 0 starting from rest
![d = \frac{1}{2}at^2](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%5E2)
![t^2 = \frac{2d}{a}](https://tex.z-dn.net/?f=t%5E2%20%3D%20%5Cfrac%7B2d%7D%7Ba%7D)
for bike
![d+25 = 0 + \frac{1}{2}*4.40t^2](https://tex.z-dn.net/?f=d%2B25%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2A4.40t%5E2)
![t^2= \frac{d+25}{2.20}](https://tex.z-dn.net/?f=t%5E2%3D%20%5Cfrac%7Bd%2B25%7D%7B2.20%7D)
equating time of both
![\frac{2d}{a} = \frac{d+25}{2.20}](https://tex.z-dn.net/?f=%5Cfrac%7B2d%7D%7Ba%7D%20%3D%20%5Cfrac%7Bd%2B25%7D%7B2.20%7D)
solving for d we get
d = 132 m
therefore t is![= \sqrt{\frac{2d}{a}}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%7B%5Cfrac%7B2d%7D%7Ba%7D%7D)
![t = \sqrt{\frac{2*132}{3.70}}](https://tex.z-dn.net/?f=t%20%3D%20%20%5Csqrt%7B%5Cfrac%7B2%2A132%7D%7B3.70%7D%7D)
t = 8.45 sec
each travelled in time 8.45 sec as
for car
![d = \frac{1}{2}*3.70 *8.45^2](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A3.70%20%2A8.45%5E2)
d = 132.09 m
fro bike
![d = \frac{1}{2}*4.40 *8.45^2](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A4.40%20%2A8.45%5E2)
d = 157.08 m
The answer is the electron microscope. It is a kind of
microscope that uses electrons to light a sample and make an enlarged
image. These kinds of microscopes have much better determining
power than light microscopes and can get much higher magnifications.