Answer:
4.75 m/s^2
Explanation:
The rate of change of velocity is called acceleration.
initial velocity, u = 15 m/s along east
Final velocity, v = 40 m /s along north
time, t = 9 s
![\overrightarrow{u} = 15\widehat{i}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bu%7D%20%3D%2015%5Cwidehat%7Bi%7D)
![\overrightarrow{v} = 40\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D%20%3D%2040%5Cwidehat%7Bj%7D)
Change in velocity,
![\overrightarrow{v}-\overrightarrow{u}=40\widehat{j}-15\widehat{i}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D-%5Coverrightarrow%7Bu%7D%3D40%5Cwidehat%7Bj%7D-15%5Cwidehat%7Bi%7D)
Acceleration,
![\overrightarrow{a}=\frac{40\widehat{j}-15\widehat{i}}{9}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Ba%7D%3D%5Cfrac%7B40%5Cwidehat%7Bj%7D-15%5Cwidehat%7Bi%7D%7D%7B9%7D)
Magnitude of acceleration
= 4.75 m/s^2
Answer:
Lithium and Sodium
Explanation:
Lithium and Sodium is in the same group 1A
Answer:
The electric flux though each face of the cube is 0.0942 Nm²/C.
Explanation:
The expression for the electric flux through the cuboid is given by:
![\phi_E=E\times A=\frac {q}{\epsilon_0}](https://tex.z-dn.net/?f=%5Cphi_E%3DE%5Ctimes%20A%3D%5Cfrac%20%7Bq%7D%7B%5Cepsilon_0%7D)
Since, area of cuboid = 6a²
![\phi_E=E\times 6a^2=\frac {q}{\epsilon_0}](https://tex.z-dn.net/?f=%5Cphi_E%3DE%5Ctimes%206a%5E2%3D%5Cfrac%20%7Bq%7D%7B%5Cepsilon_0%7D)
Where,
E is the electric field
a is the side of the cuboid
q is the charge
is the constant having value 8.85×10⁻¹² C²/Nm²
Thus, the expression for the electric flux through one face of the cuboid is given by:
![\phi_E=E\times a^2=\frac {q}{6\times \epsilon_0}](https://tex.z-dn.net/?f=%5Cphi_E%3DE%5Ctimes%20a%5E2%3D%5Cfrac%20%7Bq%7D%7B6%5Ctimes%20%5Cepsilon_0%7D)
So,
Given ,
q = 5.0×10⁻¹² C
![\phi_E=\frac {5\times 10^{-12}\ C}{6\times 8.85\times 10^{-12}\ C^2N^{-1}m^{-2}}](https://tex.z-dn.net/?f=%5Cphi_E%3D%5Cfrac%20%7B5%5Ctimes%2010%5E%7B-12%7D%5C%20C%7D%7B6%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%5C%20C%5E2N%5E%7B-1%7Dm%5E%7B-2%7D%7D)
Solving,
<u>The electric flux though each face of the cube is 0.0942 Nm²/C.</u>
<u></u>
Work of a spring:
W = 0.5 × k × x²
k spring constant
x stretch of the spring
make sure to convert all quantities into the correct units before using the equation