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Leviafan [203]
4 years ago
15

BRAINLIESTTT ASAP!!! PLEASE HELP ME :))

Chemistry
1 answer:
lys-0071 [83]4 years ago
3 0

Answer:

Multiply 1.25 by 0.04 and divide the result obtained by 1,000

Explanation:

Since there is .04 oz in 1 gram, we take the 1.25 gram and multiply by .04.

Next, to convert per liter to per milliliter, we divide by 1,000.

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A 1.10 M HCl solution prepared from 190.0 mL of a 7.0 M HCl
IrinaK [193]

Answer:

1,209mL or 1.209L

Explanation:

For this equation you would use M1V1=M2V2

You would plug (1.10M)( XmL)=(7.0M)(190.0mL)

Then you would solve for X

XmL= \frac{(7.0M)(190.0mL)}{1.10M}

XmL- 1,209mL

8 0
4 years ago
.........................................
poizon [28]

Answer:

Mhmmm I Agree

Explanation:

Its Because I Strongly Agree

7 0
4 years ago
PLEASE ANSWER FAST!!!!!!
lara31 [8.8K]

Answer:

A  by 0,5 cubic centimeters

Explanation:

If you use the density equation:

d=\frac{mass}{volume}→v=\frac{m}{d}

For A:

v=\frac{9[g]}{10g/cm^3} =0,9[cm^3]

For B:

v=\frac{4[g]}{10g/cm^3} =0,4[cm^3]

Doing the difference A-B=0,5 cubic centimeter

3 0
4 years ago
Read 2 more answers
A cylindrical specimen of some metal alloy having an elastic modulus of 129 GPa and an original cross-sectional diameter of 4.4
miss Akunina [59]

Explanation:

The cross-sectional area of the specimen is calculated as follows.

         A_{o} = \frac{pi}{4} d^{2}

                     = \frac{3.14}{4} \times (\frac{4.4}{1000})^{2}

                     = 1.5197 \times 10^{-5} m^{2}

Equation of stress is as follows.

              \sigma = \frac{F}{A_{o}}

And, the equation of strain is as follows.

             \epsilon = \frac{\Delta l}{l_{o}}

Hence, the Hook's law is as follows.

              E = \frac{\sigma}{\epsilon}

       E = \frac{\frac{F}{A_{o}}}{\frac{\Delta l}{l_{o}}}

          = \frac{F \times l_{o}}{A_{o} \times \Delta l}

or,    l_{o} = \frac{E \times \Delta l \times A_{o}}{F}          

                   = \frac{129 \times 10^{9} \times \frac{0.48}{1000} \times 1.662 \times 10^{-5}}{1570}

                  = 0.6554 m

or,         l_{o} = 655.4 mm

Thus, we can conclude that the maximum length of the specimen before deformation if the maximum allowable elongation is 0.48 mm is 655.4 mm.

5 0
4 years ago
Which of the following is a pure substance that cannot be broken down into simpler substances by chemical means?
kifflom [539]

Answer: c

Explanation:

Chemical element, please if you now the answers of my two last questions help me

4 0
3 years ago
Read 2 more answers
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