1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pie
3 years ago
14

2 Na

Chemistry
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

B Nacl is a correct

Explanation:

Nacl is a correct

You might be interested in
What is the ultimate end of a high mass star that has a core about 2.8x the mass of our sun?
jolli1 [7]

Answer:

A

Explanation:

It is formed after the star has ended its star cycle into a supernova. The star collapsed into a neutron star that is smaller than the progenitor star but has inherited angular momentum. IT, therefore, spins faster emitting electromagnetic radiation that seems to pulsate.

5 0
3 years ago
Read 2 more answers
Large masses Of flowing ice called blank are typically found near earths poles and in other cold regions
bixtya [17]
Larges of flowing ice called glaciers are typically found near Earth's poles and other cold regions.

5 0
2 years ago
Read 2 more answers
Benzoic acid, c6h5cooh, has a ka = 6.4 x 10-5. what is the concentration of h3o+ in a 0.5 m solution of benzoic acid? 3.2 x 10-5
FinnZ [79.3K]
The answer for this issue is: 
The chemical equation is: HBz + H2O <- - > H3O+ + Bz- 
Ka = 6.4X10^-5 = [H3O+][Bz-]/[HBz] 
Let x = [H3O+] = [Bz-], and [HBz] = 0.5 - x. 
Accept that x is little contrasted with 0.5 M. At that point, 
Ka = 6.4X10^-5 = x^2/0.5 
x = [H3O+] = 5.6X10^-3 M 
pH = 2.25
(x is without a doubt little contrasted with 0.5, so the presumption above was OK to make) 
3 0
3 years ago
At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 165 minutes, her sample has decayed to 5.
Paul [167]
The half-life equation is written as:

An = Aoe^-kt

We use this equation for the solution. We do as follows:

5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes? 
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE


Find a formula for G(t) , the amount of goo remaining at time t.G(t)=? 

G(t) = 176e^-0.02t

How many grams of goo will remain after 50 minutes? 

G(t) = 176e^-0.02(50) = 64.75 g
6 0
3 years ago
What do ionic compounds form
Snowcat [4.5K]

Answer:

By the result of the formation of positive and negative ions, Ionic compounds are formed.

Explanation:

Electrons are actually transferred from one atom to another to form rare gas electron structures for each ion. The atom which forms a positive ion loses electrons to the atom which gains electrons to form a negative ion. A compound is not stable unless the number of electrons which are lost and gained are equal

3 0
3 years ago
Other questions:
  • Which of the following is an anion?<br> A. O2- <br> B. Mg2+ <br> C. Al3+ <br> D. H
    10·1 answer
  • A water molecule is composed of two hydrogen atoms and one oxygen atom arranged in a bent shape. Since oxygen is significantly m
    10·2 answers
  • Match the following words with their definitions.
    12·1 answer
  • When testing water for chemical impurities, results are often reported as BDL, that is, below detection limit. The following are
    8·1 answer
  • The chemical equation of photosynthesis includes 6O2. What does the small number after the O represent?
    11·1 answer
  • M → M+ + e- reduction or oxidation?
    6·1 answer
  • If the vapor pressure of an aqueous solution containing 6.00 moles of a nonvolatile solute has a vapor pressure of 19.8 torr, an
    13·1 answer
  • What is the simplest form of matter that can exist under lab conditions
    10·1 answer
  • a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what
    11·1 answer
  • 4. A galvanic cell is formed when two metals are immersed in solu- tions differing in concentration 1 when two different metals
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!