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mote1985 [20]
2 years ago
5

When you get to the snow, you grab a handful to take back to the beach. However, by the time you get there, the snow has disappe

ared, and you are left with water dripping down your arm.
​
Physics
1 answer:
Crank2 years ago
5 0

Answer:

it has overly melted due to the heat

Explanation:

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An object is thrown upwards with a velocity of 3 meters per second, such that the only force acting on it is gravity (accelerati
3241004551 [841]

Answer:

Correct answer:  A.)  V = - 16.6 m/s down

Explanation:

Given:

V₀ = 3 m/s  initial velocity

t = 2 seconds

g = 9.8 m/s²

V(t) = V(2) = ?

The movement described is a vertical upward shot

For velocity at any time is valid the next formula

V = V₀ - g · t

V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down

Under condition that it has a enough drop height with respect to the ejection point.

God is with you!!!

3 0
4 years ago
Read 2 more answers
You drop an ice cube into an insulated bottle full of water and wait for the ice cube to completely melt. The ice cube initially
AVprozaik [17]

Answer:

T_{f}  = 17º C

Explanation:

This is a calorimetry problem, where heat is yielded by liquid water, this heat is used first to melt all ice, let's look for the necessary heat (Q1)  

Let's reduce the magnitudes to the SI system  

      Ice m = 80.0 g (1 kg / 1000 g) = 0.080 kg  

            L = 3.33 105 J / kg  

Water  M = 860 g = 0.860 kg  

           c_{e} = 4186 J / kg ºC

    Q₁ = m L  

     Q₁ = 0.080 3.33 10⁵

     Q₁ = 2,664 10⁴ J

Now let's see what this liquid water temperature is when this heat is released  

      Q = M c_{e} ΔT = M c_{e} (T₀₁ -T_{f1})  

      Q₁ = Q  

     T_{f1} = T₀₁ - Q / M ce  

     T_{f1} = 26.0 - 2,664 10⁴ / (0.860 4186)  

     T_{f1} = 26.0 - 7.40  

     T_{f1} = 18.6 ° C  

The initial temperature of water that has just melted is T₀₂ = 0ª  

The initial temperature of the liquid water is T₀₁= 18.6  

     m c_{e} T_{f} + M c_{e} T_{1} = M c_{e} T₀₁ - m c_{e} T₀₂o2  

         T_{f} = (M To1 - m To2) / (m + M)  

         T_{f} = (0.860 18.6 - 0.080 0) / (0.080 + 0.860)  

T_{f} = 17º C

 

gg

4 0
3 years ago
Compared to a maritime tropical air mass, a maritime polar air mass has?
Nastasia [14]
Continental air masses are characterized by dry air near the surface while maritime air masses are moist. Polar air masses are characterized by cold air near the surface while tropical air masses are warm or hot. ... Maritime polar (mP) air masses are cool, moist, and unstable.
8 0
3 years ago
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What is the impulse that a car with mass of 5kg experiences when its velocity changes from -9m/s to 25m/s?
Amiraneli [1.4K]

Answer:

170 kg m/s

Explanation:

Impulse = change in momentum

J = m Δv

J = (5 kg) (25 m/s − (-9 m/s))

J = 170 kg m/s

4 0
3 years ago
Read 2 more answers
Which equation correctly relates mechanical energy, thermal energy, and total
Anna35 [415]

Answer:

B

This is because frictional energy is similar to thermal energy in a system. Therefore the thermal energy produced is equal to

8 0
3 years ago
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