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vagabundo [1.1K]
3 years ago
10

When light bulbs A and B are connected in series to a battery, A glows brightly and B glows dimly. You remove bulb B so that the

circuit is just the battery and bulb A and connect bulb B to an identical battery.With the two bulbs connected to identical batteries but in separate circuits, do they glow equally brightly now? a. Bulb A glows brighter b. The two bulbs glow equally brighty. c. Bulb B glows brighter.
Physics
2 answers:
torisob [31]3 years ago
6 0

Answer:

The bulb B glows brighter.

Explanation:

Given that,

A glows brightly and B glows dimly.

According to ohm's law,

Two light bulbs A and B are connected in series to a battery then the current will be same in both bulbs and the resistance is high of bulb A and low in bulb B.

If bulb A connect to a battery and bulb B connect to a same battery separately.

Then bulb B glows brighter because the resistance is high in bulb A so the current will be low.

The resistance is low in bulb B so the current will be high.

Hence, The bulb B glows brighter.

JulsSmile [24]3 years ago
5 0

Answer:

Explanation:

When the two bulbs A and B are connected in series, the current is same in both the bulbs. Power is given by

P = i²R

so, as the bulb A is glowing more than the B, so the resistance of A is more than B.

Now they are connected seperately by two indentical batteries. The potential difference is same in both the bulbs.

Power is given by

P = V²/R

as the resistance of B is smaller than the resistance of A, so the brightness of bulb B is more than A.

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Firstly, let's calculate the momentum of both objects using p=mv:

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Object 2 (we will make this one negative as it is travelling in the opposite direction):
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Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

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1.695 = 1.4v
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Answer:

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Visible light refers to the part of the spectrum which has wavelength between 380 nm and 750 nm. These are the only electromagnetic wave that our eyes can see, and depending on their wavelength, they appear as a different color. In particular, each color corresponds to a different range of wavelengths:

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Answer:

r=5.278\times 10^{-4}\ m

Explanation:

Given that:

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<em>Now, form the mathematical expression of Kinetic Energy:</em>

KE= \frac{1}{2} m.v^2

1.92\times 10^{-19}=0.5\times 9.1\times 10^{-31}\times v^2

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v=6.496\times 10^6\ m.s^{-1}

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