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Blababa [14]
3 years ago
14

explain each of the following kinds of rockets: Solid-Fuel Rocket, Liquid-Fuel Rocket, Ion Rocket and Plasma Rocket.

Engineering
1 answer:
Rudik [331]3 years ago
5 0

Answer:

ur answer friend

Explanation:

answer

<em>S</em><em>o</em><em>l</em><em>i</em><em>d</em><em>-</em><em>F</em><em>u</em><em>e</em><em>l</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>a solid-propellant rocket or solid rocket is a rocket with a rocket engine that uses solid propellants. The earliest rockets were solid-fuel rockets powered by gunpowder; they were used in warfare by the Chinese, Indians, Mongols and Persians, as early as 13th century.

<em>L</em><em>i</em><em>q</em><em>u</em><em>i</em><em>d</em><em>-</em><em>F</em><em>u</em><em>e</em><em>l</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>a liquid-propellant rocket or liquid rocket utilizes a rocket engine that use liqiud propellants. An inert gas stored in a tank at a high pressure is sometimes used instead of pumps in simpler small engines to force the propellants into the combustion chamber.

<em>I</em><em>o</em><em>n</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>an ion thruster or ion drive is a form of electric propulsion used for spacecraft propulsion. It creates thrust by accelerating ions using electricity. The Deep Space 1 spacecraft, powered by an ion thruster, changed velocity by 4.3 km/s ( 9600 mph ) while consuming less than 74 kg ( 163 lb ) of xenon.

<em>P</em><em>l</em><em>a</em><em>s</em><em>m</em><em>a</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>in this type of rocket, a combination of electric and magnetic fields are used to break down the atoms and molecules of a propellant gas into a collection of particles that have either a positive charge (ions) or a negative charge (electrons). In other words, the propellant gas becomes a plasma.

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Aleks04 [339]

Answer:

The answer is "I = 0.0085106383 \ A"

Explanation:

Given:

R= 470  \ \Omega \\\\V= 4 \ v

Formula:

\to V=IR\\\\\to I = \frac{V}{R}\\\\

      = \frac{4}{470}\\\\ = 0.0085106383 \ A

3 0
3 years ago
Which of the following statements about glycogen metabolism is FALSE?
Ratling [72]

Answer:

Glycogen is the primary energy source for muscle and liver cells.

Explanation:

Glycogen is a readily mobilized storage form of glucose. It is a very large, branched polymer of glucose residues that can be broken down to yield glucose molecules when energy is needed. Most of the glucose residues in glycogen are linked by α-1,4-glycosidic bonds. Branches at about every tenth residue are created by α-1,6-glycosidic bonds.

Glycogen is not as reduced as fatty acids are and consequently not as energy rich. Why do animals store any energy as glycogen? Why not convert all excess fuel into fatty acids? Glycogen is an important fuel reserve for several reasons. The controlled breakdown of glycogen and release of glucose increase the amount of glucose that is available between meals. Hence, glycogen serves as a buffer to maintain blood-glucose levels. Glycogen's role in maintaining blood-glucose levels is especially important because glucose is virtually the only fuel used by the brain, except during prolonged starvation. Moreover, the glucose from glycogen is readily mobilized and is therefore a good source of energy for sudden, strenuous activity. Unlike fatty acids, the released glucose can provide energy in the absence of oxygen and can thus supply energy for anaerobic activity.

3 0
4 years ago
A compressed-air drill requires an air supply of 0.25 kg/s at gauge pressure of 650 kPa at the drill. The hose from the air comp
Klio2033 [76]

Answer:

L = 46.35 m

Explanation:

GIVEN DATA

\dot m  = 0.25 kg/s

D = 40 mm

P_1 = 690 kPa

P_2 = 650 kPa

T_1 = 40° = 313 K

head loss equation

[\frac{P_1}{\rho} +\alpha \frac{v_1^2}{2} +gz_1] -[\frac{P_2}{\rho} +\alpha \frac{v_2^2}{2} +gz_2] = h_l +h_m

whereh_l = \frac{ flv^2}{2D}

h_m minor loss

density is constant

v_1 = v_2

head is same so,z_1 = z_2

curvature is constant so\alpha = constant

neglecting minor losses

\frac{P_1}{\rho}  -\frac{P_2}{\rho} = \frac{ flv^2}{2D}

we know\dot m is given as= \rho VA

\rho =\frac{P_1}{RT_1}

\rho =\frac{690 *10^3}{287*313} = 7.68 kg/m3

therefore

v = \frac{\dot m}{\rho A}

V =\frac{0.25}{7.68 \frac{\pi}{4} *(40*10^{-3})^2}

V = 25.90 m/s

Re = \frac{\rho VD}{\mu}

for T = 40 Degree, \mu = 1.91*10^{-5}

Re =\frac{7.68*25.90*40*10^{-3}}{1.91*10^{-5}}

Re = 4.16*10^5 > 2300 therefore turbulent flow

for Re =4.16*10^5 , f = 0.0134

Therefore

\frac{P_1}{\rho}  -\frac{P_2}{\rho} = \frac{ flv^2}{2D}

L = \frac{(P_1-P_2) 2D}{\rho f v^2}

L =\frac{(690-650)*`10^3* 2*40*10^{-3}}{7.68*0.0134*25.90^2}

L = 46.35 m

5 0
3 years ago
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gizmo_the_mogwai [7]

Answer:

I can share a link to answer since the code is to long to be contained here. the code is on github

https://github.com/arafatm/edu_coursera_machine_learning_1_foundations/blob/master/code/02.01.predicting.house.prices.ipynb

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3 years ago
Electronic highway message boards communicate how
kakasveta [241]

Answer:

with words giving information about the road ahead.

Explanation:

7 0
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