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inessss [21]
3 years ago
9

How do the circulatory system and the respiratory system work together?

Physics
2 answers:
Softa [21]3 years ago
8 0

Answer:

The circulatory system tends to pump blood around the whole body, while the respiratory system tend to facilitate the exchange of gas in the body so then the blood will look totally fresh. In simpler terms, the heart is connected to the lungs through the means of arteries and veins.

Explanation:

mezya [45]3 years ago
5 0
The circulatory system tends to pump blood around the whole body, while the respiratory system tend to facilitate the exchange of gas in the body so then the blood will look totally fresh. In simpler terms, the heart is connected to the lungs through the means of arteries and veins.

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the loss of a partical such as a proton as an atom tries to become stable is called A.) an isotope B.) Radioactive decay C.) Rad
Arte-miy333 [17]
The answer would be B
4 0
3 years ago
Read 2 more answers
A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
3 years ago
A soccer player kicks a 0.44 kg ball with a force of 57.6 N, what is the ball’s acceleration
noname [10]

THE BALL'S ACCELERATION IS 130.90\frac{m}{s}

Explanation:

According to Newton's second law "the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)", meaning that when the soccer player kicks a ball, a force is acting on the ball, therefore increasing it's acceleration

SO FOR CALCULATING THIS WE WILL USE NEWTON LAW,

   FORCE = MASS × ACCELERATION

WE ARE GIVEN

FORCE = 57.6N

MASS= .44KG

SO HERE WE APPLYING FORMULA ,WE WILL GET

ACCELERATION = \frac{FORCE}{MASS}

ACCELERATION = \frac{57.6N}{.44KG}

ACCELERATION =130.90\frac{m}{s}

8 0
3 years ago
When you enter a toll road, your ticket is stamped 1:00 p.m. When you leave, after traveling 55 miles, your ticket is stamped 2:
Viefleur [7K]
27.5 because of you divide the 55miles with the time you get your velocity which is the speed.
4 0
3 years ago
Read 2 more answers
Math Focus
zhenek [66]

Answer: 4.

Explanation:

Use formula v = d / t, where v = speed, d = distance and t = time.

v = 10 / 2.5

v = 4.

3 0
3 years ago
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