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babymother [125]
4 years ago
6

Which is true according to the kinetic theory?

Chemistry
2 answers:
iragen [17]4 years ago
8 0

Answer: C. all particles of matter move very quickly

Explanation:

Heat is how fast the molecules are moving in something. This means even  a solid's molecules are moving.

zavuch27 [327]4 years ago
6 0

Answer:   C.

Explanation:

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When an atom in a reactant loses electrons, what happens to its oxidation number? A. Its oxidation number decreases. B. Its oxid
Neko [114]

ANSWER:

its oxidation number increases

~batmans wife dun dun dun..aka ~pizza ninja

6 0
4 years ago
Read 2 more answers
6.50 g of a certain Compound x, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 1
gayaneshka [121]

Answer:

C_{10}H_8

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to find the molecular formula of the given compound by firstly calculating both moles and grams of carbon in carbon dioxide and hydrogen in water, as the only sources of these elements derived from the compound x due to its combustion:

n_C=22.35gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.51molC\\\\m_C=0.51molC*\frac{12.01gC}{1molC}   =6.10gC

n_H=3.66gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}=0.41molH\\\\m_H=0.41molH*\frac{1.01gH}{1molH}=0.41g

Now, since the addition of carbon and hydrogen is about 6.50 grams, we infer the compound has no oxygen, that is why we now set the mole ratios in the empirical formula for both C and H as shown below:

C:\frac{0.51mol}{0.41mol}= 1.24\\\\H:\frac{0.51mol}{0.51mol}= 1\\\\C_{1.24}H

Yet it cannot be decimal, that is why we multiply by 4 to get the correct whole-numbered empirical formula:

C_5H_4

Whose molar mass is 64.09 g/mol, which makes the ratio of molar masses:

\frac{128.g/mol}{64.09g/mol} =2

Therefore, the molecular formula is twice the empirical one:

C_{10}H_8

Regards!

8 0
3 years ago
(Numerical problems) A car is running with the velocity of 72km/h. What will be it's velocity after 5s if it's acceleration is -
kodGreya [7K]

The car's velocity after 5s : 10 m/s

<h3>Further explanation</h3>

Given

velocity=v=72 km/h=20 m/s

time=t = 5 s

acceleration=a = -2 m/s²

Required

velocity after 5s

Solution

Straight motion changes with constant acceleration

\tt v_f=v_i+at

vf=final velocity

vi = initial velocity

Input the value :

\tt v_f=20+(-2).5\\\\v_f=20-10\\\\v_f=10~m/s

The car is decelerating (acceleration is negative) so that its speed decreases

4 0
3 years ago
During the light-independent reaction, carbon dioxide is fixed by adding it to a A. 2-carbon compound B. 3-carbon compound C. 4-
Scrat [10]
During the light independent reaction, carbon dioxide is fixed by adding it to a <span>5-carbon compound</span>
8 0
4 years ago
Read 2 more answers
What is the [oh−] of a solution with ph 5.75
Gekata [30.6K]
[ H₃O⁺] = 10 ^- pH

[ H₃O⁺] = 10 ^ (- 5.75 )

[H₃O⁺] = 1.778x10⁻⁶ M

Kw = [ H₃O⁺] x [ OH⁻]

1x10⁻¹⁴ = 1.778x10⁻⁶ x [OH⁻]

[OH⁻] = 1x10⁻¹⁴ / 1.778x10⁻⁶

[OH⁻] = 5.62x10⁻⁹ M

hope this helps!
5 0
3 years ago
Read 2 more answers
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