The speed of the combined balls after the collision is about 0.67 m/s to the left

<h3>Further explanation</h3>
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !

<em><u>Complete Question:</u></em>
<em>A 100 g ball moving to the right at 4.0 m/s collides head-on with a 200 g ball that is moving to the left at 3.0 m/s.</em>
<em>If the collision is </em><em>perfectly inelastic</em><em>, what is the speed of the combined balls after the collision? What is the direction of the combined balls after the collision?</em>
<u>Given:</u>
mass of first ball = m₁ = 100 g
mass of second ball = m₂ = 200 g
initial speed of first ball = u₁ = 4.0 m/s <em>( + sign means right direction )</em>
initial speed of second ball = u₂ = -3.0 m/s <em>( - sign means left direction )</em>
final speed of both balls = v₁ = v₂ = v <em>( perfectly inelatic collision )</em>
<u>Asked:</u>
final speed of both balls = ?
<u>Solution:</u>
<em>We will use </em><em>Conservation of Momentum Law </em><em>as follows:</em>








<h3>Conclusion :</h3>
Both balls are moving to the left at about 0.67 m/s.

<h3>Learn more</h3>

<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Dynamics