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kykrilka [37]
4 years ago
15

A ball has an electric charge of +1.5 × 10-9 coulombs. At what distance from the ball's center is the electric field strength eq

ual to 5.8 × 105 newtons/coulomb?
(k = 9.0 × 109 newton·meter2/coulomb2)

0.2 × 10-2 meters
4.8 × 10-3 meters
3.0 × 10-2 meters
5.8 × 105 meters

Please help I keep failing this quiz. -_-
Physics
2 answers:
frutty [35]4 years ago
6 0

Answer:

Distance, d=4.8\times 10^{-3}\ m

Explanation:

It is given that,

Electric charge on a ball, q=1.5\times 10^{-9}\ C

Electric field strength, E=5.8\times 10^5\ N/C

The electric field strength is given by :

E=k\dfrac{q}{d^2}

r=\sqrt{\dfrac{kq}{E}}

r=\sqrt{\dfrac{9\times 10^9\times 1.5\times 10^{-9}}{5.8\times 10^5}}

r = 0.0048 meters

or

r=4.8\times 10^{-3}\ m

Hence, the correct option is (b).

dimaraw [331]4 years ago
5 0
E=Fe/q                                                      
5.8x10^5N/C=Fe/(1.5x10^-9C)             
Fe=(5.8x10^5N/C)(1.5x10^-9C)
Fe=8.7x10^-4N

Fe=kq1q2/r²
8.7X10^-4N=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/r²
r²=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/(8.7x10^-4N)
√r²=√0.00002325
The final answer is r=4.8x10-3m

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3 0
3 years ago
A grating has 460 rulings/mm. What is the longest wavelength for which there is a 6.0th-order diffraction line
mestny [16]

Answer:

λ = 3.62 x 10⁻⁷ m = 362 nm

Explanation:

The grating equation gives the relationship between the wavelength, the diffraction line order and the diffraction angle. The grating equation is written as follows:

mλ = d Sinθ

where,

m = order of diffraction = 6

λ = longest wavelength = ?

d = 1/(460 rulings/mm)(1000 mm /1 m) = 2.17 x 10⁻⁶ m/ruling

θ = Diffraction angle = 90° (for longest wavelength)

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3 0
4 years ago
A parallel RC circuit has a capacitive reactance of 962 ohms and a resistance of 1,200 ohms what is the impedance of this circui
Alex777 [14]

Answer:

<em>A. 751 ohm</em>

Explanation:

Impedance: <em>This is the total opposition to the flow of current in an a.c circuit by any or all of the three circuit elements ( R, L, C). The unit of impedance is Ohms (Ω). The impedance in a parallel circuit is gives a s</em>

<em>Z = RXₐ/√(Xₐ² + R²)............................... Equation 1</em>

<em>Where Z = The impedance of the a.c circuit, Xₐ = capacitive reactance, R = resistance.</em>

<em>Given: Xₐ = 962 Ω, R = 1200 Ω</em>

<em>Substituting these values into equation 1,</em>

<em>Z = 962×1200/√(962² + 1200²)</em>

<em>Z = 1154400/√(925444 + 1440000)</em>

<em>Z = 1154400/√(925444+1440000</em>

<em>Z = 1154400/1538</em>

<em>Z = 750.59 Ω</em>

<em>Z≈ 751 Ω</em>

<em>Therefore the impedance of the circuit = 751 Ω</em>

<em>The right option is A. 751 ohm</em>

6 0
4 years ago
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