Answer:
Average speed in east direction
Explanation:
We have given average speed of the entire trip = 5 km/hr
First the car 4 hours then travels 12 km in 4 hours
So total time of the trip = 4+4 = 8 hours
So total distance traveled in the trip ![d=speed\times time = 5\times 8=40km](https://tex.z-dn.net/?f=d%3Dspeed%5Ctimes%20time%20%3D%205%5Ctimes%208%3D40km)
As the car travel 12 km in 4 hours to the west
So distance traveled in 4 hour in east = 40 -12 = 28 km
Time in east direction = 4 hour
So average speed in east direction ![speed=\frac{distance}{time}=\frac{28}{4}=7km/hr](https://tex.z-dn.net/?f=speed%3D%5Cfrac%7Bdistance%7D%7Btime%7D%3D%5Cfrac%7B28%7D%7B4%7D%3D7km%2Fhr)
<span>A measurement
that both magnitude and direction is a vector quantity. An example of this is a
moving car. The car exerts force due to its thrust and weight that runs in it. This
will give us the magnitude of the car. The resulting motion of the car in terms
of displacement, velocity and acceleration that determines its direction makes
it a vector quantity. On the other hand, a measurement that has only magnitude is
a scalar quantity. The energy exerted by the engine of the car is a scalar
quantity.</span>
ANSWER: 1.6N (forth option)
EXPLANATION:
E= Force x displacement
69=F(42)
69/42 = F
F=1.64 N
Answer : 1.6N
That is FALSE. The equation to calculate the charges has a distance component that is in the denominator which means that it is inversely proportional (as the distance os greater the force is smaller)
The person driving the truck was killed
the wall was destroyed