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ryzh [129]
3 years ago
8

A lot of points, pls help. i need it done asap

Physics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

I think it's how far out the water goes from the beach before the tsunami because before tsunami usually the water goes back way behind the tide before tsunami and that tells them everything they need I think

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What do submarines translate into pictures?
prohojiy [21]
It lets the viewer know it's something to do with underwater.
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Describe two examples of how humans use electromagnetic waves.
Alex73 [517]
Electromagnetic waves are used in everyday life. You are looking at your computer screen right now. The light that is coming off of the screen is visible light, a form of electromagnetic radiation. Electromagnetic waves are also used to send information. For example, AM or FM radios are radio waves that transfer sound information to your local radio.
5 0
3 years ago
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How much energy ( in joules ) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature ?
aleksley [76]

Answer:

B. 17,705.1 J

Explanation:

The hear released when the mercury condenses into a liquid is given by:

Q=m \lambda_v

where

m = 0.06 kg is the mass of the mercury

\lambda_v is the latent heat of vaporization

For mercury, the latent heat of vaporization is \lambda_v = 296 kJ/kg, so the heat released during the process is:

Q=(0.06 kg)(296 kJ/kg)=17.76 kJ = 17,760 J

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B. 17,705.1 J

5 0
3 years ago
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PLEASE HELP ME WITH THIS ONE QUESTION
sdas [7]

Answer:

0.34 m

Explanation:

From the question,

v = λf................ Equation 1

Where v = speed of sound, f = frequency, λ = Wave length

Make λ the subject of the equation

λ = v/f............... Equation 2

Given: v = 340 m/s, f = 500 Hz.

Substitute these values into equation 2

λ = 340/500

λ = 0.68 m

But,  the distance between a point of rarefaction and the next compression point, in the resulting sound is half wave length

Therefore,

λ/2 = 0.68/2

λ/2 = 0.34 m

Hence, the distance between a point of rarefaction and the next compression point, in the resulting sound is 0.34 m

6 0
2 years ago
Student pushes a 50 N block across the floor for a distance of 15 m how much work was done to move the block
Talja [164]

Answer:

750 J

Explanation:

We have a student that pushes a 50N block  across the floor for a distance of 15m. The question is asking how much work was done to move the block.

To solve this, we must know that we are looking for a certain thing called joules. And to get the answer, we must follow the formula of W = FS

F being the force and S being the distance.

W = FS

W = (50)(15)

W = 750

Therefore, 750 joules is our answer.

7 0
3 years ago
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