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Sedaia [141]
3 years ago
10

15. Brandon weighs 600 newtons. What is his mass? *

Physics
1 answer:
Harman [31]3 years ago
7 0

Answer:

I believe it is B

Explanation:

Not sure

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Which of the following expressions for power or dimensionally correct?
Slav-nsk [51]

Power=F.V

dimension: ML^2T^-2


8 0
3 years ago
A 60.0 kg girl stands up on a stationary floating raft and decides to go into shore. She dives off the 180 kg floating raft with
padilas [110]
Momentum, p = m.v
m of the girl = 60.0 kg
m of the boat = 180 kg
v of the girl = 4.0 m/s

A) Momentum of the girl as she is diving:
p = m.v = 60.0 kg * 4.0 m/s = 24.0 N/s

B) momentum of the raft = - momentum of the girl = -24.0 N/s

C) speed of the raft

p = m.v ; v = p/m = 24.0N/s / 180 kg = -0.13 m/s [i.e. in the opposite direction of the girl's velocity]
8 0
3 years ago
A scooter is traveling at a constant speed v when it encounters a circular hill of radius r = 480 m. The driver and scooter toge
Grace [21]

Answer:

68.585m/sec , 779.1 N

Explanation:

To feel weightless, centripetal acceleration must equal g (9.8m/sec^2). The accelerations then cancel.

From centripetal motion.

F =( mv^2)/2

But since we are dealing with weightlessness

r = 480m

g = 9.8m/s^2

M also cancels, so forget M.

V^2 = Fr

V = √ Fr

V =√ (9.8 x 480) = 4704

= 68.585m/sec.

b) Centripetal acceleration = (v^2/2r) = (68.585^2/960) = 4704/960

= 4.9m/sec^2.

Weight (force) = (mass x acceleration) = 159kg x (g - 4.9)

159kg × ( 9.8-4.9)

159kg × 4.9

= 779.1N

6 0
3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
bazaltina [42]

Answer:

The current in the rods is 171.26 A.

Explanation:

Given that,

Length of rod = 0.85 m

Mass of rod = 0.073 kg

Distance d = 8.2\times10^{-3}\ m

The rods carry the same current in the same direction.

We need to calculate the current

I is the current  through each of the wires then the force per unit length on each of them is

Using formula of force

\dfrac{F}{L}=\dfrac{\mu_{0}I^2}{2\pi d}

\dfrac{mg}{L}=\dfrac{\mu_{0}I^2}{2\pi d}

Where, m = mass of rod

l = length of rod

Put the value into the formula

I^2=\dfrac{mgd}{\mu L}

I^2=\dfrac{0.073\times9.8\times8.2\times10^{-3}}{2\times10^{-7}}

I=\sqrt{29331.4}

I=171.26\ A

Hence, The current in the rods is 171.26 A.

5 0
3 years ago
-science
Misha Larkins [42]

Answer:

variations in great horned owl body size due to food supply can be acted on by natural selection.

Explanation:

Natural selection can help select great horned owl with smaller body size since it's an advantage in a place with smaller available food sources, compared to a bigger body size that will need more food. At first, birds with smaller body survive while those bigger ones die out, and the smaller birds pass on this genes to their offspring.

Answer:

variation in body size due to inherited traits can be acted on by natural selection

Explanation :

Variations in body size in body size due to inherited trait can be acted upon by natural selection by favoring the size that is best suited for the survival of the species. Those with these genes survive and pass it on to their offspring, while those with the unfavorable body size are wiped out.

3 0
3 years ago
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