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3 years ago

-science

Physics

1 answer:

Misha Larkins [42]3 years ago

3 0

Answer:

variations in great horned owl body size due to food supply can be acted on by natural selection.

Explanation:

Natural selection can help select great horned owl with smaller body size since it's an advantage in a place with smaller available food sources, compared to a bigger body size that will need more food. At first, birds with smaller body survive while those bigger ones die out, and the smaller birds pass on this genes to their offspring.

Answer:

variation in body size due to inherited traits can be acted on by natural selection

Explanation :

Variations in body size in body size due to inherited trait can be acted upon by natural selection by favoring the size that is best suited for the survival of the species. Those with these genes survive and pass it on to their offspring, while those with the unfavorable body size are wiped out.

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A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b

jonny [76]

Answer:

Part a)

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

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Explanation:

Part a)

Level of sound = 75 dB

now we know that

$L = 10 Log\frac{I}{I_0}$

here we know that

$I_0 = 10^{-12} W/m^2$

now we have

$75 = 10 Log(\frac{I}{10^{-12}})$

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

Intensity of sound wave is given as

$I = \frac{1}{2}\rho A^2\omega^2 c$

here we know that

$A = \frac{P_o}{Bk}$

so we have

$I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c$

$I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}$

now we know

$\rho = 1.2 kg/m^3$

$c = 340 m/s$

$B = 1.4 \times 10^5 Pa$

now we have

$3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}$

$P_o = 0.162 Pa$

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I think it’s D) all of the above

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Read 2 more answers

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user100 [1]

Answer:

4.2 is the answer

Explanation

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Step 1: the equation to this problem would be: 8.4/2

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2 years ago

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Answer:

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Explanation:

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