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zubka84 [21]
3 years ago
13

A 60.0 kg girl stands up on a stationary floating raft and decides to go into shore. She dives off the 180 kg floating raft with

a velocity of 4.0 m/s [W]. Ignore the substantial friction real objects in water experience.
A) What is the momentum of the girl as she is diving?
B) What is the momentum of raft as the girl is diving?
C) What is the final speed of the raft just after the girl dives?
Physics
1 answer:
padilas [110]3 years ago
8 0
Momentum, p = m.v
m of the girl = 60.0 kg
m of the boat = 180 kg
v of the girl = 4.0 m/s

A) Momentum of the girl as she is diving:
p = m.v = 60.0 kg * 4.0 m/s = 24.0 N/s

B) momentum of the raft = - momentum of the girl = -24.0 N/s

C) speed of the raft

p = m.v ; v = p/m = 24.0N/s / 180 kg = -0.13 m/s [i.e. in the opposite direction of the girl's velocity]
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<u>Explanation</u>

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Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{Mm}{r^{2}} (1)

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M=5.972(10)^{24} kg is the mass of the Earth

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Where a_{C} is the centripetal acceleration given by:

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Being V the orbital velocity of the moon

Making (1)=(2):

m.a_{C}=G\frac{Mm}{r^{2}} (4)

Simplifying:

a_{C}=G\frac{M}{r^{2}} (5)

Making (5)=(3):

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Finding V:

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Finally:

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