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zubka84 [21]
3 years ago
13

A 60.0 kg girl stands up on a stationary floating raft and decides to go into shore. She dives off the 180 kg floating raft with

a velocity of 4.0 m/s [W]. Ignore the substantial friction real objects in water experience.
A) What is the momentum of the girl as she is diving?
B) What is the momentum of raft as the girl is diving?
C) What is the final speed of the raft just after the girl dives?
Physics
1 answer:
padilas [110]3 years ago
8 0
Momentum, p = m.v
m of the girl = 60.0 kg
m of the boat = 180 kg
v of the girl = 4.0 m/s

A) Momentum of the girl as she is diving:
p = m.v = 60.0 kg * 4.0 m/s = 24.0 N/s

B) momentum of the raft = - momentum of the girl = -24.0 N/s

C) speed of the raft

p = m.v ; v = p/m = 24.0N/s / 180 kg = -0.13 m/s [i.e. in the opposite direction of the girl's velocity]
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S_A_V [24]

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Explanation:

The jumping motion of the Salmon can be modelled as the projectile motion. So, we use the formula for the range of projectile motion here:

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where,

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V₀² = 3.04 m/(0.10126 s²/m)

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<u>V₀ = 5.47 m/s</u>

6 0
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In a drill during basketball practice, a player runs the length of the 30-meter court and back. The player does this three times
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0 m/s

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As the player runs the court and returns to the original point. It would mean that the shortest path covered is 0.

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Hence, the correct option is (1).

6 0
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