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Anit [1.1K]
3 years ago
10

Use synthetic division to detemine if x+1 is a factor of f(x) for f(x) x^3-7x^2+8x+16

Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0

Answer:

It is a factor

Step-by-step explanation:

[x³ -7x² + 8x + 16] ÷ (x + 1)

[x³ + x² - 8x² - 8x + 16x + 16] ÷ (x + 1)

[x²(x + 1) - 8x(x + 1) + 16(x + 1)] ÷ (x + 1)

x² - 8x + 16 and tye remainder is 0.

So, yes (x + 1) is a factor

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Which set of ordered pairs does not represent a function? \{(5, -9), (6, -6), (-3, 8), (9, -6)\}{(5,−9),(6,−6),(−3,8),(9,−6)} \{
Nady [450]

Answer:

\{(-6, -4), (4, -8), (-6, 9), (1, -3)\}

Step-by-step explanation:

Given

\{(5, -9), (6, -6), (-3, 8), (9, -6)\}

\{(-6, -4), (4, -8), (-6, 9), (1, -3)\}

\{(1, -1), (-5, 7), (4, -9), (-9, 7)\}

\{(8, -9), (-3, -6), (-4, 4), (1, -5)\}

Required

Which is not a function

An ordered pair is represented as:

\{(x_1,y_1),(x_2,y_2),(x_3,y_3),..........,(x_n,y_n)\}

However, for the ordered pair to be a function; all the x values must be unique (i.e. not repeated)

<em>From options (a) to (d), option (b) has -6 repeated twice. Hence, it is not a function.</em>

4 0
3 years ago
Can you guys please help me? I understand everything but the last step.​
MariettaO [177]

Answer:

It is because you have to get rid of the power of 2 from c. In order to get rid, you have to square root it on both sides :

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