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svetlana [45]
3 years ago
10

How many total electrons are there in a water molecule4102

Physics
1 answer:
andre [41]3 years ago
3 0
10 electrons are in a water molecule. :)
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State the methods of nuclear fission waste disposal and the suitability of each method.
Alexeev081 [22]
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Radioactive wastes are stored so as to avoid any chance of radiation exposure to people, or any pollution.The radioactivity of the wastes decays with time, providing a strong incentive to store high-level waste for about 50 years before disposal.Disposal of low-level waste is straightforward and can be undertaken safely almost anywhere.Storage of used fuel is normally under water for at least five years and then often in dry storage.<span>Deep geological disposal is widely agreed to be the best solution for final disposal of the most radioactive waste produced.

</span>I suggest this site on this subject http://www.world-nuclear.org/information-library/nuclear-fuel-cycle/nuclear-wastes/storage-and-dispo...
5 0
3 years ago
Energy transformations when you cook sausages on a campfire burning wood
Rina8888 [55]

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8 0
3 years ago
Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work? Move the machine to a
Lady bird [3.3K]
Reduce the friction. Since the total energy is conserved, the only way to improve its work capacity is by reducing energy that doesnt go into work.
7 0
3 years ago
Read 2 more answers
A suitcase (mass m = 18 kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures
Sindrei [870]

Answer:

P=2736 Pa

Explanation:

According to Newton we have that:

∑F=m*a\\

A force is exerted by the elevator to the suitcase, according to 3th Newton's law an equal force but in the opposite direction will appeared on the suitcase, that is:

∑F=m*g+m*a=m*(g+a)

F=205.2N

We know that the pressure is given by:

P=\frac{F}{A}\\P=\frac{205.2N}{(0.50m)*(0.15m)}\\P=2736N/m^2=2736Pa

6 0
3 years ago
Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of
navik [9.2K]

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

7 0
3 years ago
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