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Illusion [34]
3 years ago
5

A system consists of electrons and protons only. It contains 150 electrons and has a total charge of +22e. What is the mass of t

he system? me=9.11×10−31kg, mp=1.673×10−27kg.
Physics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

Mass of system will be 288.605\times 10^{-28}kg

Explanation:

We have given a system consist 150 electrons

Mass of one electron m_{e}=9.1\times 10^{-31}kg

So mass of 150 electron =150\times 9.1\times 10^{-31}=1365\times 10^{-31}=1.365\times 10^{-28}kg

Charge on system is +22e

So number of proton = 150 +22 = 172

Mass of one proton =1.67\times 10^{-27}kg

So mass of 172 proton =172\times 1.67\times 10^{-27}=287.24\times 10^{-27}=287.24\times 10^{-28}kg

So total mass on the system =287.24\times 10^{-28}+1.365\times 10^{-28}=288.605\times 10^{-28}kg

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A steel beam that is 5.50 m long weighs 332 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending
ElenaW [278]

Explanation:

The given data is as follows.

    Length of beam, (L) = 5.50 m

    Weight of the beam, (W_{b}) = 332 N

     Weight of the Suki, (W_{s}) = 505 N

After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

                 \sum M_{o} = 0

     -W_{s} \times x + W_{b} \times 1.5 = 0

                x = \frac{W_{b} \times 1.5}{W_{s}}

                   = \frac{332 N \times 1.5}{505 N}

                   = 0.986 m

Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.

Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.

8 0
4 years ago
NEED HELP
aniked [119]

Answer:

I = 0.25 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.

V = I*R

where:

V = voltage [Volt]

I = amperage or current [amp]

R = resistance [ohm]

Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.

Rt = 2 + 8 + 14

Rt = 24 [ohm]

Now clearing I for amperage

I = V/Rt

I = 6/24

I = 0.25 [amp].

5 0
3 years ago
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