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3 years ago

The frequency of the given sound is 1.5khz then how many vibration it is completing in one second ?

Physics

2 answers:

Amanda [17]3 years ago

8 0

Answer: The answer is 1500 per second.

Explanation: Each vibration consist 1.5 kilohertz, so I multiply 1000 and the number of the kilohertz that looks like this, 1.5*1000=1500 per second, I hoped my answer is very helpful to your own physics question and have a Happy Halloween! :D

Sincerely,

Jason Ta,

The ambitious of Brainly and the role of the TDSB and WHCI Student of the high school.

kompoz [17]3 years ago

6 0

Answer:

1500 per second.

Explanation:

vibrations = 1.5 kilohertz

1.5×1000=1500

the answer is 1500 per second.

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Plain electromagnetic wave (in air) has a frequency of 1 MHz and its B-field amplitude is 9 nT a. What is the wavelength in air?

Norma-Jean [14]

Answer:

Part a)

$\lambda = 300 m$

Part b)

$E = 2.7 N/C$

Part c)

$I = 9.68 \times 10^{-3} W/m^2$

$P = 3.22 \times 10^{-11} N/m^2$

Explanation:

Part a)

As we know that frequency = 1 MHz

speed of electromagnetic wave is same as speed of light

So the wavelength is given as

$\lambda = \frac{c}{f}$

$\lambda = \frac{3\times 10^8}{1\times 10^6}$

$\lambda = 300 m$

Part b)

As we know the relation between electric field and magnetic field

$E = Bc$

$E = (9 \times 10^{-9})(3\times 10^8)$

$E = 2.7 N/C$

Part c)

Intensity of wave is given as

$I = \frac{1}{2}\epsilon_0E^2c$

$I = \frac{1}{2}(8.85 \times 10^{-12})(2.7)^2(3\times 10^8)$

$I = 9.68 \times 10^{-3} W/m^2$

Pressure is defined as ratio of intensity and speed

$P = \frac{I}{c} = \frac{9.68\times 10^{-3}}{3\times 10^8}$

$P = 3.22 \times 10^{-11} N/m^2$

6 0

3 years ago

A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has

Novay_Z [31]

Answer:

3.07 m/s

Explanation:

6 0

3 years ago

A flat, wide cloud floats horizontally a few kilometers above the surface of Earth. Its lower surface carries a uniform surface

valentinak56 [21]

Answer:

$\frac{kQ}{r^2} r^$

Explanation:

Electric field strength= Force/unit charge

E= (kQq/r²)/q ₓ r

where r is the unit vector in the direction of unit charge

E= $\frac{kQ}{r^2} r^$

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3 years ago

5. a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m. Calculate

omeli [17]

Answer:

<h3>The answer is 2 s</h3>

Explanation:

The time of flight can be found by using the formula

$t = \frac{d}{v} \\$

d is the distance covered

v is the velocity

From the question we have

$t = \frac{100}{50} = \frac{10}{5} \\$

We have the final answer as

Hope this helps you

8 0

3 years ago

A parallel plate capacitor filled with air with plate area 2-cm2 and plate separation of 0.5 mm is connected to a 12 V batter an

pashok25 [27]

Answer:

a) The charge of the capacitor is 4.25x10⁻¹¹C

b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.

c) The potential difference across the plates is 18 V

d) The work is 7.64x10⁻¹⁰J

Explanation:

The capacitance of the capacitor is equal to:

$C=\frac{e_{0}A }{d}$

A = 2 cm² = 0.0002 m²

d = 0.5 mm = 0.0005 m

Replacing:

$C=\frac{8.85x10^{-12}*0.0002 }{0.0005} =3.54x10^{-12} F = 3.54pF$

a) The charge of the capacitor is equal to:

Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C

b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)

c) If distance is increased, we have:

$C=\frac{8.85x10^{-12}*0.0002 }{0.00075} =2.36x10^{-12} F=2.36pF$

The potential is:

$V=\frac{Q}{C} =\frac{42.48}{2.36} =18V$

d) The work done is equal to:

$W=VQ=18*42.48=764.6pJ=7.64x10^{-10} J$

3 0

3 years ago

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The frequency of the given sound is 1.5khz then how many vibration it is completing in one second ?​

The frequency of the given sound is 1.5khz then how many vibration it is completing in one second ?