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salantis [7]
4 years ago
8

The nuclear charge an electron actually experiences is called the ___ nuclear charge (Zeff). This charge is always ___ than the

actual nuclear charge since in many-electron systems the electrons ___ each other from the nucleus.
Chemistry
1 answer:
svetlana [45]4 years ago
5 0

Answer:

1. <u>Effective</u> nuclear charge (Zeff)

2. <u>Less</u>

3.<u> Shield</u>

Explanation:

The <u>effective</u> nuclear charge (Zeff) is defined as the <em>nuclear charge that is experienced</em> by an electron of an atom having atomic number > 1.

The effective nuclear charge experienced by a given electron is always <u>less</u> than the actual nuclear charge of the nucleus of the atom. This is because of the shielding effect of the inner electrons of the atom.

The shielding effect is defined as the shielding of an electron from the positive nuclear charge of the nucleus by the inner electrons of an atom.  

Therefore, the outer electrons of an polyelectronic atom are <u>shielded</u> by the inner electrons from the nuclear charge of the nucleus.

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When heated, allyl aryl ethers and allyl vinyl ethers undergo a reaction called a Claisen rearrangement, a concerted reorganizat
Alex_Xolod [135]

Answer:

See explanation below

Explanation:

I found a picture of this exercise, to show you how to do this problem.

The first picture is the compound, and the second is the mechanism of reaction to do this claisen rearrangement.

Hope this helps

5 0
3 years ago
SOMEONE PLEASE HELP
Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

= 8.16 \times 10^{ - 6} \:  kg

\boxed{density =  \frac{mass}{volume} }

Density of iron bar

=  \frac{0.0642}{8.16 \times 10^{ - 6} }

= 7870 kg/m³ (3 s.f.)

7.

\boxed{mass = density \:  \times volume}

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

= 12  \times  10^{ - 6}  \: m^{3}  \\  = 1.2 \times 10^{ - 5}  \: m ^{3}

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

=  \frac{0.151} {1.25 \times 10^{ - 5} }  \\  = 12600 \: kg/ {m}^{3}

(3 s.f.)

6 0
3 years ago
How many particles are in 5.00 grams of nitric acid?
Leto [7]

Answer:

0.0500

Explanation:

7 0
3 years ago
Why is argon monoatomic in nature​
siniylev [52]
Argon monatomic in nature because it is a noble gas and has completely filled shells and thus does not form a bond with other elements.
7 0
3 years ago
The equilibrium constant for the gas-phase isomerization of borneol (c10h17oh) to isoborneol at 503 k is 0.106. a mixture consis
Dimas [21]
The solution is as follows:

K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106

The molar mass of isoborneol/borneol is 154.25 g/mol

Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol

Use the ICE approach

        borneol  →  isoborneol
I         0.0972           0.0486
C         -x                     +x
E     0.0972 - x        0.0486 + x

Total moles = 0.1458

Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P

0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832 

Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
6 0
4 years ago
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