Explanation:
Depression in Freezing point
= Kf × i × m
where m is molality , i is Van't Hoff factor, m = molality
Since molality and Kf remain the same
depression in freezing point is proportional to i
i= 2 for CuSO4 ( CuSO4----------> Cu+2 + SO4-2
i=1 for C2h6O
i= 3 for MgCl2 ( MgCl2--------> Mg+2+ 2Cl-)
So the freezing point depression is highest for MgCl2 and lowest for C2H6O
so freezing point of the solution = freezing point of pure solvent- freezing point depression
since MgCl2 has got highest freezing point depression it will have loweest freezing point and C2H6O will have highest freezing point
Hello!
The Chemical reaction is the following:
2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)
If we assume that all the gases are ideal gases,
we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:

So,
2 L of Water Vapor reacts with the fluorine; and
1 L of Oxygen and
4 L of Hydrogen Fluoride are produced.
Have a nice day!
Answer: V2= 0.224L
Explanation:
P1=3.55atm, V2= 7.35L, T1= 290, P2= 123atm, V2=?, T2= 307K
Applying general gas equation
P1V1/T1= P2V2/T2
Substitute and Simplify
3.55×7.35/290 = 123×V2/307
V2= 0.224L