What would cause an atom to have a high electronegativity value?

Isoleucine, leucine, lysine, methionine, phenylalanine, threonine, tryptophan, and valine are known as the ____.

Sveta_85 [38]

The answer is amino acids :). hope that helped!

4 0

4 years ago

A 20-kg wagon accelerates on a horizontal surface at 0.50 m⁄s2 when pulled by a rope exerting a 120-N force on the wagon at an a

inn [45]

Answer:

Explanation:

given,

mass of wagon = 20 Kg

horizontal acceleration = 0.5 m/s²

force of pull = 120 N

angle with horizontal = 25°

Applying newtons second law

F cos θ - f = m a

f = F cos θ- ma

f = 120 cos 25° - 20 x 0.5

f = 99 N

we know,

f = μ N

μ = $\dfrac{f}{N}$

μ = $\dfrac{99}{mg - Fsin \theta}$

μ = $\dfrac{99}{20\times 9.8 - 120 sin 25^0}$

μ = 0.68

5 0

4 years ago

A 68-kg skydiver has a speed of 52 m/s at an altitude of 670 m above the

Arlecino [84]

Answer:

91936J

Explanation:

We know that kinetic energy= 1/2 mv^2

M= mass = 68 Kg

v= velocity= 52 m/s

KE=1/2 × 68 × (52)^2

KE= 1/2 × 68 × 2704

KE= 91936J

4 0

3 years ago

Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

Taya2010 [7]

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

So

$I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})$

The dB can be calculated as:

$dB=10log(I_{n})\\$

Substitute the given values

$dB=10log(1.08*10^{11})\\dB=110.32dB$

So the sound intensity level they would experience without the earplugs is 110.32dB.

7 0

3 years ago

Moustapha jones drives east at 100km/hr for 3 hours then back west at 80km/hr for 1.5 hours. which pair of answers gives his ave

olya-2409 [2.1K]

The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.

The total distance cover in east direction is=100*3=300 km

The total distance cover in the west direction=80*1.5=120 km

The total distance covered is =300+120=420 km

And Total displacement of the car is =300-120=180 km

As we know that the average speed is given as

Avg Speed =Total Distance / Total time

=420/4.5=93.33 km/hr

As we know that the average velocity is given as

Avg Speed =Total Displacement/ Total time

=180/4.5=40 km/hr

Therefore, The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.

7 0

4 years ago