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inessss [21]
2 years ago
7

Can someone answer these question for me?​

Physics
1 answer:
kap26 [50]2 years ago
4 0

Answer:

search it

Explanation:

then you will see it

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Two concrete spans of a 250-m-long bridge are placed end to end so that no room is allowed for expansion. If a temperature incre
scoundrel [369]

Answer:

  y = 2.74 m

Explanation:

The linear thermal expansion processes are described by the expression

         ΔL = α L ΔT

Where α the thermal dilation constant for concrete is 12 10⁻⁶ºC⁻¹, ΔL is the length variation and ΔT the temperature variation in this case 20ªc

If the bridge is 250 m long and is covered by two sections each of them must be L = 125 m, let's calculate the variation in length

        ΔL = 12 10⁻⁶ 125 20

        ΔL = 3.0 10⁻² m

Let's use trigonometry to find the height

The hypotenuse     Lf = 125 + 0.03 = 125.03 m

Adjacent leg           L₀ = 125 m

       cos θ = L₀ / Lf

       θ = cos⁻¹ (L₀ / Lf)

       θ = cos⁻¹ (125 / 125.03)

       θ = 1,255º

We calculate the height

       tan 1,255 = y / x

       y = x tan 1,255

       y = 125 tan 1,255

       y = 2.74 m

3 0
3 years ago
How does mass effect potential and kinetic energy on a roller coaster?
PilotLPTM [1.2K]
Potential energy is measured by mass * gravity * height. So, the larger the mass on a roller coaster, the more potential energy it has. 

Also, the higher it is, the more potential energy it has. 
6 0
3 years ago
A car speeds up as it rolls down a hill. Which is this an example of? A. positive acceleration B. negative acceleration C. relat
alina1380 [7]
I believe it is A. positive acceleration since it is speeding up
4 0
3 years ago
A particle leaves the origin with an initial velocity v = (3.00 i hat) m/s and a constant acceleration a = (-3.00 i hat - 1.400
Brilliant_brown [7]

Answer:

a)  —0.5 j m/s  

b) 4.5 i + 2.25 j m

Explanation:

<u>Givens:</u>

v_0 =3.00 i m/s

a= (-3 i — 1.400 j ) m/s^2  

The maximum x coordinate is reached when dx/dt = 0 or v_x = 0 ,thus :

<em>v_x = v_0 + at = 0  </em>

(3.00 i m/s) + (-3 i m/s^2)t=0

t = (3 m/s)/-3 i m/s^2

t = -1 s

Therefore the particle reaches the maximum x-coordinate at time t = 1 s.  

Part a The velocity-of course- is all in the y-direction,therefore:

v_y =v_0+ at

We have that v_0 = 0 in the y-direction.

v_y = (-0.5 j m/s^2)(1 s)

      = —0.5 j m/s  

Part b: While the position of the particle at t = 1 s is given by:

r=r_0+v_0*t+1/2*a*t^2

Where r_0 = 0 since the particle started from the origin.

Its position at t = 1 s is then given by :

r =(3.00 i m/s)(1 s)+1/2(-3 i — 1.400 j )(1 s)^2

 =4.5 i + 2.25 j m

8 0
3 years ago
Small force=
Nataliya [291]

Answer:

weight force (i.e. the weight of something)

the force of a bat on the ball.

the force of the hair brush on hair when it is being brushed.

the force of your foot pushing on the pedal when you ride your bike.Explanation:

4 0
3 years ago
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