Answer:
C₅H₈NO₄Na
Explanation:
Step 1: Given data
- Percentage by mass of Na in MSG: 13.6%
- Percentage by mass of C in MSG: 35.5%
- Percentage by mass of H in MSG: 4.8%
- Percentage by mass of N in MSG: 8.3%
- Percentage by mass of O in MSG: 37.8%
Step 2: Divide each percentage by the atomic mass of the element
Na: 13.6/22.99 = 0.592
C: 35.5/12.01 = 2.96
H: 4.8/1.01 = 4.75
N: 8.3/14.00 = 0.592
O: 37.8/16.00 = 2.36
Step 3: Divide all the number by the smallest one, i.e. 0.592
Na: 0.592/0.592 = 1
C: 2.96/0.592 = 5
H: 4.75/0.592 ≈ 8
N: 0.592/0.592 = 1
O: 2.36/0.592 ≈ 4
The empirical formula of MSG is C₅H₈NO₄Na.
The arrow is between 4.0 and 5.0, so the measurement is at least 4.0. The arrow is between the third and fourth small tick marks, so it’s at least 0.3. We will have to estimate the last place. It looks like about one-third of the way across the space, so let us estimate the hundredths place as 3. The symbol psi stands for “pounds per square inch” and is a unit of pressure, like air in a tire)
Answer:
=2h20−2kmno4+2mno2+2ckl+cl2+4hko+o2
Explanation:
step-by-step.
2mno2+4koh+o2+cl2−2kmno4+2kcl+2h20
=2mno2+4hko+o2+cl2+−2kmno4+2ckl+2h20
The theoretical yield of iron metal : 16.418 g
<h3>Further explanation</h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
2 Fe₂O₃ + 3 C ⇒ 4 Fe + 3 CO₂
mol Fe₂O₃ (MW=159,69 g/mol) :
mol Fe₂O₃ : mol Fe = 2 : 4
mol Fe :
mass Fe(the theoretical yield) :
Answer:
0.992 g/L
Step-by-Step Explanation:
We can use the <em>Ideal Gas Law</em> to calculate the density of the gas.
pV = nRT
n = m/M Substitute for n
pV = (m/M)RT Multiply both sides by M
pVM = mRT Divide both sides by V
pM = (m/V) RT
ρ = m/V Substitute for m/V
pM = ρRT Divide each side by RT
ρ = (pM)/(RT)
===============
p = 1.00 atm
M = 28.01 g/mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 71.1 °C = 344.25 K Solve for ρ
===============
ρ = (1.00 × 28.01)/(0.082 06 × 344.25)
ρ = 28.01/28.25
ρ = 0.992 g/L