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Tatiana [17]
3 years ago
8

A race car accelerates from 0.00m/s to 40.0m/s with a displacement of 50.0m. What was the cars

Physics
1 answer:
Vladimir79 [104]3 years ago
7 0

Answer:

Explanation:

Using the equation of motion v² = u²+2as

v is the final velocity = 40m/s

u is the iniyail velocity 0m/s

a is the acceleration

s is the displacement

Substituting in the formula;

40² = 0²+2a(50)

1600 = 100a

Divide both sides by 100

100a/100 = 1600/100

a = 16

Hence the car acceleration is 16m/s²

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The combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8
qwelly [4]

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\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}

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\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}

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