A baseball with a mass of 0.8 kg is given an acceleration of 20m/s.how much force was applied to the ball
1 answer:
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Answer:0.27
Explanation:
Given
One worker Pushes with force
other Pulls it with a rope of rope
mass of crate
both forces are horizontal and crate slides with a constant speed
Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it
where is the friction force
where is the coefficient of static friction
Answer:
1317.4 m
Explanation:
We are given that
Angle=
Initial speed =
We have to find the horizontal distance covered by the shell after 5.03 s.
Horizontal component of initial speed=
Vertical component of initial speed=
Time=t=5.03 s
Horizontal distance =
Using the formula
Horizontal distance=
Horizontal distance=1317.4 m
Hence, the horizontal distance covered by the shell=1317.4 m