A baseball with a mass of 0.8 kg is given an acceleration of 20m/s.how much force was applied to the ball

NASA is designing a mission to explore Titan, the largest moon of Saturn. Titan has numerous hydrocarbon lakes containing a mix

Vitek1552 [10]

Answer:

Total pressure in atmosphere IS 4.36 atm

Explanation:

Given Data:

Depth of lake is 400 mtr

surface tension is 147 kilopascals

surface temperature 94 kelvin

Gravity = 1.35 m/s^2

specific gravity of methane(liquid) = 0.415

specific gravity of ethane(liquid) = 0.546

density of methane can be obtained as

$\rho_{methane} = 0.415\times 1000 = 415 kg/m^3$

Density of ethane can be obtained as

$\rho_{ethane} = 0.546\times 1000 = 546 kg/m^3$

Total pressure in atmosphere can be obtained as

$P = surface\ tension + \rho_{max}gh$

$= 147 +546\times 1.35\times 400\times 10^{-3}$

= 441.84 kPa

$= 441.84\times 0.009869 atm\kPa$

= 4.36 atm

7 0

2 years ago

Make a list of principle of lever.

vivado [14]

Answer:

The force applied to make the object move

8 0

2 years ago

Read 2 more answers

Why caring a body and moving with it is not a work done Why :

Alecsey [184]

Answer:

Work done on an object is equal to

FDcos(angle).

So, naturally, if you lift a book from the floor on top of the table you do work on it since you are applying a force through a distance.

However, I often see the example of carrying a book through a horizontal distance is not work. The reasoning given is this: The force you apply is in the vertical distance, countering gravity and thus not in the direction of motion.

But surely you must be applying a force (and thus work) in the horizontal direction as the book would stop due to air friction if not for your fingers?

Is applying a force through a distance only work if causes an acceleration? That wouldn't make sense in my mind. If you are dragging a sled through snow, you are still doing work on it, since the force is in the direction of motion. This goes even if velocity is constant due to friction.

Explanation:

8 0

2 years ago

A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary

Ann [662]

The distance traveled by the wood after the bullet emerges is 0.16 m.

The given parameters;

mass of the bullet, m = 23 g = 0.023 g
speed of the bullet, u = 230 m/s
mass of the wood, m = 2 kg
final speed of the bullet, v = 170 m/s
coefficient of friction, μ = 0.15

The final velocity of the wood after the bullet hits is calculated as follows;

$m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s$