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4 years ago

What must always be true if a covalent bond is to be polar?

Chemistry

2 answers:

scZoUnD [109]4 years ago

8 0

Answer:

If a covalent bond is polar the electronegativity difference between the elements of the compound is between 0.4 and 1.7

Explanation:

The electronegativity measures the power of an atom to attract electrons; if the electronegativity difference between the elements of the compound is big (more than 1.7) the compound will be ionic, that means, an atom or a group of atoms will give electrons and another atom of group of atoms will receive them; if the electronegativity difference is small (less than 0.4), the electrons will be shared by the atoms in a equitative way, i. e. the electrons will spend similar amount of time in the orbitals of each atom; but if the electronegativity difference is between 0.4 and 1.7 a covalent polar bond will be formed, that means valence electrons will spend more time in the orbitals of the most electronegative element.

Aleksandr [31]4 years ago

4 0

N a polar covalent bond<span>, the electrons shared by the atoms spend a greater amount of time, on the average, closer to the Oxygen nucleus than the Hydrogen nucleus. This is because of the geometry of the molecule and the great electronegativity difference between the Hydrogen atom and the Oxygen atom.</span>

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If there are 3.10 moles of O, how many moles of each of the compounds are present?

Burka [1]

Explanation:

The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.

H2SO4

1 mol of H2SO4 contains 4 mol of O

x mol of H2SO4 would contain 3.10 mol of O

x = 3.10 * 1 / 4 = 0.775 mol of H2SO4

C2H4O2

1 mol of C2H4O2 contains 2 mol of O

x mol of C2H4O2 would contain 3.10 mol of O

x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2

NaOH

1 mol of NaOH contains 1 mol of O

x mol of NaOH would contain 3.10 mol of O

x = 3.10 * 1 / 1 = 3.10 mol of NaOH

3 0

3 years ago

Using the diagram below, which rock layer is older than the Chinle Formation?

Klio2033 [76]

Answer:

moenkopi formation because layers further down are always older. think about it as a pile of laundry the clothes at the bottom of the pile were worn earlier in the week and are older and dirtier.

Explanation:

also pls mark brainliest <3 :)))

3 0

3 years ago

Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U

Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

or,

$(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}$ ..........(1)

where,

$R_1$ = rate of effusion of nitrogen gas = $79mL/s$

$R_2$ = rate of effusion of sulfur dioxide gas = ?

$M_1$ = molar mass of nitrogen gas = 28 g/mole

$M_2$ = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

$(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}$

$R_2=52mL/s$

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0

3 years ago

How does urban sprawl affect water consumption?

Vesnalui [34]

Answer:

Urban sprawl is the development in urban areas

Due to which people are migrating from rural areas to urban areas to get the jobs or their income sources due to the opportunities.

So, as population is increasing in the urban areas. The food consumption and water consumption will also increase.

So, this is how urban sprawl affect water consumption.

5 0

3 years ago

Read 2 more answers

A sample of gas (1.9 mol) is in a flask at 21 °C and 697 mm Hg. The flask is opened and more gas is added to the flask. The new

Artyom0805 [142]

Answer: There are now 2.07 moles of gas in the flask.

Explanation:

$PV=nRT$

P= Pressure of the gas = 697 mmHg = 0.92 atm (760 mmHg= 1 atm)

V= Volume of gas = volume of container = ?

n = number of moles = 1.9

T = Temperature of the gas = 21°C=(21+273)K= 294 K (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

$V=\frac{nRT}{P}=\frac{1.9\times 0.0821 \times 294}{0.92}=49.8L$

When more gas is added to the flask. The new pressure is 775 mm Hg and the temperature is now 26 °C, but the volume remains same.Thus again using ideal gas equation to find number of moles.

$PV=nRT$

P= Pressure of the gas = 775 mmHg = 1.02 atm (760 mmHg= 1 atm)

V= Volume of gas = volume of container = 49.8 L

n = number of moles = ?

T = Temperature of the gas = 26°C=(26+273)K= 299 K (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

$n=\frac{PV}{RT}=\frac{1.02\times 49.8}{0.0821\times 299}=2.07moles$

Thus the now the container contains 2.07 moles.

6 0

3 years ago