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bekas [8.4K]
4 years ago
8

An explosion inside a nuclear plant resulted in an exposure of 250 Rem/hr. (2 miles away). How far will you have to move away to

decrease your exposure to 2 Rem/hr.?
Physics
1 answer:
makkiz [27]4 years ago
7 0

Answer:

f something happens to go wrong at a nuclear reactor, anyone living in a 10-mile radius of the plant may have to evacuate. This map also shows a 50-mile evacuation zone, the safe distance that the U.S. government recommended to Americans who were near

because

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A lightbulb has a power of 100 W and is used for 4 hours. A microwave has a power of 1200 W and is used for 5 minutes. How much
ladessa [460]

Answer:

a. E=1440KJ

b. E=360KJ

c. E=1.8 J

Explanation:

I have the power (Watts) is expressed as Energy (Joules) / Time (seconds), also I have to1hour * \frac{60min}{1hour}*\frac{60s}{1min}\\1h=3600s

so, for the lightbulb

100W= \frac{Energy}{3600s*4}\\Energy=100W*14400s\\ E=1440000J =1440KJ

Analogously, for the microwave

1200W= \frac{Energy}{60s*5}\\Energy=1200W*300s\\ E=360000J =360KJ

Now, I have to express the efficiency as Heat energy / power * 100 so1.8= \frac{Heat Energy}{100W}*100\\Heat Energy=1.8J

Done

4 0
4 years ago
When large amplitude sound vibrates the ear significantly, a _______ results.
kondaur [170]
D loud sound

Hope this helped:)
4 0
3 years ago
Read 2 more answers
If the Hubble Space Telescope is 598 m above the surface of the Earth and is traveling at 7.56 x 103 m/s, how long does it take
viva [34]

Answer:

5069.04 seconds

Explanation:

The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.

It is given as:

T = \sqrt{\frac{4\pi^2r^3 }{GM} }

where r = radius of orbit of Hubble Space Telescope

G = gravitational constant = 6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}

M = Mass of earth

We are given that:

r = radius of the earth + distance of HST from earth

r = 6.38 * 10^6 + 598 = 6380598 m

M = 5.98 * 10^{24} kg

Therefore, T will be:

T = \sqrt{\frac{4*\pi^2 * 6380598^3 }{6.67408 * 10^{-11} * 5.98 * 10^{24}}}

T = 5069.04 secs

The orbital period of the Hubble Space Telescope is 5069.04 seconds.

7 0
3 years ago
Read 2 more answers
Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of
Charra [1.4K]

To solve the problem it is necessary to apply the Torque equations and their respective definitions.

The Torque is defined as,

\tau = I \alpha

Where,

I=Inertial Moment

\alpha = Angular acceleration

Also Torque with linear equation is defined as,

\tau = F*d

Where,

F = Force

d= distance

Our dates are given as,

R = 30 cm = 0.3m

m = 1.5 kg

F = 20 N

r = 4.0 cm = 0.04 m

t = 4.0s

Therefore matching two equation we have that,

d*F = I\alpha

For a wheel the moment inertia is defined as,

I= mR2, replacing we have

d*F= \frac{mR^2a}{R}

d*F= mRa

a = \frac{rF}{ mR}

a = \frac{0.04*20}{1.5*0.3}

a=1.77 m/s^2

Then the velocity of the wheel is

V = a *t \\V=1.77*4 \\V=7.11 m/s

Therefore the correct answer is D.

4 0
3 years ago
Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete
almond37 [142]

Answer:

<em>work done in pumping the entire fuel is 1399761 J</em>

Explanation:

weight per volume of the gasoline = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 6 m

The height of the tractor tank above the top of the tank = 5 m

The total volume of the fuel is gotten below

we know that the tank is cylindrical.

<em>we assume that the fuel completely fills the tank.</em>

therefore, the volume of a cylinder =  

where r = radius = diameter ÷ 2 = 3/2 = 1.5 m

volume of the cylinder = 3.142 x  x 6 = 42.417 m^3

we then proceed to find the total weight of the fuel in Newton

total weight = (weight per volume) x volume

total weight = 6600 x 42.417 = 279952.2 N

therefore,

the work done to pump the fuel through to the 5 m height = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 279952.2 x 5 = <em>1399761 J</em>

5 0
3 years ago
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