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vladimir2022 [97]
4 years ago
5

Please help me and explain if you can

Chemistry
1 answer:
Virty [35]4 years ago
3 0

Answer:

Density of iron shot is 7.92 g/mL.

Explanation:

Given data:

Mass of water + iron + graduated cylinder = 94.74 g

Mass of water  + graduated cylinder = 66.24 g

Volume of water = 45.50 mL

Volume of water + iron shot = 49.10 mL

Density of iron = ?

Solution:

First of all we will calculate the volume of iron shot.

Volume of iron shot= (Volume of water + iron shot) - Volume of water

Volume of iron shot= 49.10 mL - 45.50 mL

Volume of iron shot= 3.6 mL

Now we will calculate the mass of iron shot.

Mass of iron shot = (Mass of water + iron + graduated cylinder  ) - Mass of water  + graduated cylinder

Mass of iron shot = 94.74 g -  66.24 g

Mass of iron shot = 28.5 g

Now we will calculate the density of iron shot.

d = m/v

d = 28.5 g / 3.6 mL

d = 7.92 g/mL

Density of iron shot is  7.92 g/mL.

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Answer:

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8 0
3 years ago
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the mass of one hydrogen atom is 1.67x10^-27 kg. A cylinder contains 3.01x10^23 hydrogen atoms. What is the mass of the hydrogen
VladimirAG [237]
Multiply 1.67x10^-27 by 3.01x10^23
5 0
3 years ago
Hydrogen 3 has a half life of 12.32 years a sample of h-3 weighing 3.02 grams is left for 15.0 years what will the final weight
yawa3891 [41]

Answer:

The final mass of sample is 1.3 g.

Explanation:

Given data:

Half life of H-3 = 12.32 years

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Solution:

First all we will calculate the decay constant.

t₁/₂ = ln² /k

t₁/₂ =12.32 years

12.32 y =  ln² /k

k = ln²/12.32 y

k = 0.05626 y⁻¹

Now we will find the original amount:

ln (A°/A) = Kt

ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y

ln (3.02 g/ A) = 0.8439

3.02 g/ A = e⁰°⁸⁴³⁹

3.02 g/ A = 2.33

A = 3.02 g/ 2.33

A = 1.3 g

The final mass of sample is 1.3 g.

8 0
3 years ago
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Which best describes the geologic time scale? (choose the best answer from below)
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A city's water supply is contaminated with a toxin at a concentration of 0.63 mg/L. For the water to be safe for drinking, the c
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Answer:

Approximately 22.37 days, will it take for the water to be safe to drink.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

k is rate constant

Given that:- k = 0.27 (day)⁻¹

[A_0] = 0.63 mg/L

[A_t]=1.5\times 10^{-3} mg/L

Applying in the above equation as:-

1.5\times 10^{-3}=0.63e^{-0.27\times t}

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e^{-0.27t}=\frac{1}{420}

t=\frac{100\ln \left(420\right)}{27}=22.37

<u>Approximately 22.37 days, will it take for the water to be safe to drink.</u>

7 0
3 years ago
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