Answer:
The period of oscillation is 1.33 sec.
Explanation:
Given that,
Mass = 275.0 g
Suppose value of spring constant is 6.2 N/m.
We need to calculate the angular frequency
Using formula of angular frequency
Where, m = mass
k = spring constant
Put the value into the formula
We need to calculate the period of oscillation,
Using formula of time period
Put the value into the formula
Hence, The period of oscillation is 1.33 sec.
Answer:
Explanation:
2 )
power of an electric device = V² / R where V is volts and R is resistance
putting given data
power = 9²/ 5
= 16.2 J/s
energy produced in 7 minutes
= 16.2 x 7 x 60
= 6804J .
3 ) Power of an electrical device
= V² / R
= V X I where I is current
= 4.5 x .5
= 2.25 W or J/s
4 )
energy used in 3 minutes with power of 2.25 W
= 2.25 x 3 x 60
= 405 J .
7 )
power of a electrical device
= V x I
IR x I where R is resistance .
= I²R
putting given data
power = .005² x 50
= 1.25 x 10⁻³ W .
8 )
Energy used up by a 60 W bulb in 2.5 hours
= 60 x 2.5 x 60 x 60
= 5.4 x 10⁵ J .
The masses are equal.
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
I hope that this helps you!
<span>Energy dissipated by friction is E
Initial Ei=mgh
Final Ef=1/2 mv^2
then subtracted Ef-Ei,
ΔE = 0
m g h -- E – 1/2 m v² = 0
66 (9.8) (250) - E - ½ (66)(14)² = 0
E = (9.8)(250) – ((14)^2)/2
E = 155.232kJ</span>
The question is incomplete. The complete question is :
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a compressed position. The record of time is started when the oscillating mass first passes through the equilibrium position, and the position of the mass at any time is described by x = (4.7 cm)sin[(7.9 rad/s)πt].
Determine the following:
(a) frequency of the motion
(b) period of the motion
(c) amplitude of the motion
(d) first time after t = 0 that the object reaches the position x = 2.6 cm
Solution :
Given equation : x = (4.7 cm)sin[(7.9 rad/s)πt].
Comparing it with the general equation of simple harmonic motion,
x = A sin (ωt + Φ)
A = 4.7 cm
ω = 7.9 π
a). Therefore, frequency,
= 3.95 Hz
b). The period,
= 0.253 seconds
c). Amplitude is A = 4.7 cm
d). We have,
x = A sin (ωt + Φ)
Hence, t = 0.0236 seconds.