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butalik [34]
3 years ago
13

Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. Part A If a boat and its riders h

ave a mass of 1200 kg and the boat drifts in at 1.3 m/s how much work does Sam do to stop it
Physics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

W = 1014 J = 1.014 KJ

Explanation:

As, Sam has to stop the boats in the log ride. Therefore, the work Sam needs to do, in order to stop a boat must be equal to the kinetic energy of the boat:

Work Done by Sam = Kinetic Energy of the Boat

W = K.E

W = (1/2)mv²

where,

m = mass of boat and its rider = 1200 kg

v = speed of the boat = 1.3 m/s

Therefore,

W = (1/2)(1200 kg)(1.3 m/s)²

<u>W = 1014 J = 1.014 KJ</u>

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an unknown charge exerts an attractive force of 4.23 E 13 N. If these charges are separated by 8cm, what is the magnitude of the
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Answer:

Since there is attraction force between two charges so the other charge must be - 3C

Explanation:

As we know that the force between two charges is given by formula

F = \frac{kq_1q_2}{r^2}

here we know that

F = 4.23 \times 10^{13}N

also we know that

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r = 8 cm

now we have

4.23 \times 10^{13} = \frac{(9\times 10^9)(10)q}{0.08^2}

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3 years ago
A ball rolls at 3 meters per second. how much time does it take for the ball to roll 6 meters
natka813 [3]
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As an object moves from point A to point B only two forces act onit: one force is nonconservative and does -30 J of work, the ot
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To solve this problem we will apply the principles of energy conservation. On the one hand we have that the work done by the non-conservative force is equivalent to -30J while the work done by the conservative force is 50J.

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The conservative force is linked to the movement caused by the sum of the two energies, therefore there is an increase in kinetic energy. The decrease in the mechanical energy of the system is directly due to the loss given by the non-conservative force, therefore there is a decrease in mechanical energy.

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7 0
3 years ago
A sound from a source has an intensity of 270 db when it is 1 m from the source. what is the intensity of the sound when it is 3
Lina20 [59]
Sound intensity is inversely proportional to the square of the distance between the source and the receiver.
That is 
I = k/r^2
 where
 k = constant
 r = radius

When r=1,  the intensity is I₁ = k/1 = k
When r=3, the intensity I₂ = k/3² = k/9
Therefore
 I₂ = I₁ /9

In decibels,
I = 10 log₁₀(I/I₀)
where I₀ = reference intensity

When r=1,
10 log₁₀ (I₁/I₀) = 270

When r =3,
10 log₁₀ (I₂/I₀) = 10 log₁₀ [(I₂/I₁)*(I₁/I₀)]
                     = 10 log₁₀ [(1/9)*(I₁/I₀)]
                     = 10 log₁₀(1/9) + 270
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Answer: 260.5 dB (nearest tenth)
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A park ranger wants to shoot a monkey hanging from a branch of a tree with a tranquilizing dart. The ranger aims directly at the
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