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3 years ago

3. A wye-connected load has a voltage of 480 V applied to it. What is the voltage dropped across each phase?

Physics

1 answer:

ZanzabumX [31]3 years ago

5 0

Answer:

$E_s = 277.13V$

Explanation:

Given

$Load\ Voltage = 480V$

Required

Determine the voltage dropped in each stage.

The relation between the load voltage and the voltage dropped in each stage is

$E_l = E_s * \sqrt3$

Where

$E_l = 480$

So, we have:

$480 = E_s * \sqrt3$

Solve for $E_s$

$E_s = \frac{480}{\sqrt3}$

$E_s = \frac{480}{1.73205080757}$

$E_s = 277.128129211$

$E_s = 277.13V$

<em>Hence;</em>

<em>The voltage dropped at each phase is approximately 277.13V</em>

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A train travels due north in a straight line with a constant speed of 100 m/s. Another train leaves a station 2,881 m away trave

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Answer:

The trains will collide at a distance 1660 m from the station

Explanation:

Let the train traveling due north with a constant speed of 100 m/s be Train A.

Let the train traveling due south with a constant speed of 136 m/s be Train B.

From the question, Train B leaves a station 2,881 m away (that is 2,881 m away from Train A position).

Hence, the two trains would have traveled a total distance of 2,881 m by the time they collide.

∴ If train A has covered a distance $x$ m by the time of collision, then train B would have traveled $(2881 - x)$ m.

Also,

At the position where the trains will collide, the two trains must have traveled for equal time, t.

That is, At the point of collision,

$t_{A} = t_{B}$

$t_{A}$ is the time spent by train A

$t_{B}$ is the time spent by train B

From,

$Velocity = \frac{Distance }{Time }\\$

$Time = \frac{Distance}{Velocity}$

Since the time spent by the two trains is equal,

Then,

$\frac{Distance_{A} }{Velocity_{A} } = \frac{Distance_{B} }{Velocity_{B} }$

${Distance_{A} = x$ m

${Distance_{B} = 2881 - x$ m

${Velocity_{A} = 100$ m/s

${Velocity_{B} = 136$ m/s

Hence,

$\frac{x}{100} = \frac{2881 - x}{136}$

$136(x) = 100(2881 - x)\\136x = 288100 - 100x\\136x + 100x = 288100\\236x = 288100\\x = \frac{288100}{236} \\x = 1220.76m\\$

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This is the distance covered by train A by the time of collision.

Hence, Train B would have covered (2881 - 1221)m = 1660 m

Train B would have covered 1660 m by the time of collision

Since it is train B that leaves a station,

∴ The trains will collide at a distance 1660 m from the station.

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3 years ago